The answer is p=1.71 kg m/s
Answer:
1.2 m/s
0.31 m
0.15 m
Explanation:
Time period is
Frequency is
Velocity is given by
The waves are traveling at 1.2 m/s
Amplitude is given by
Amplitude is 0.31 m
If d = 0.3 m
The amplitude would be 0.15 m. The speed would remain the same.
Answer:
g = 15.5 m/s²
Explanation:
In order to find the acceleration due to gravity near the surface of this planet can be calculated by using 2nd equation of motion. The 2nd equation of motion is given as:
h = Vi t + (0.5)gt²
where,
h = height covered by the wrench = 5 m
Vi = Initial Velocity = 0 m/s
t = Time Taken to hit the ground = 0.804 s
g = acceleration due to gravity near the surface of the planet = ?
Therefore,
5 m = (0 m/s)(0.804 s) + (0.5)(g)(0.804 s)²
g = (5 m)/(0.3232 s²)
<u>g = 15.5 m/s²</u>
Answer:
0.152 m
Explanation:
The condition for constructive interference is
d sinθ= mλ (m= 0,1,2,3...)
the slit width
d= 1/N
d= 10^(-3)/520
= 1.92×10^(-6)
The angular spread for the red light is
= 19.97°
The angular spread of blue light is
=14.66°
The distance between the first order red fringe and blue fringe is,
y= y_r- y_b = Ltanθ_r -Ltanθ_b
=1.50( tan19.97°-tan14.66°) = 0.152 m
Sum of the individual forces