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Sergio039 [100]
3 years ago
13

Which of the following activities belongs on the top of the physical activity for pyramid

Physics
1 answer:
jasenka [17]3 years ago
7 0
Playing Vedio Games. :)
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The 2 question are on the photo above.
AlekseyPX
A. power plants burn coal. A fossil-fuel power plant is one that burns fossil fuels such as coal, natural gas or petroleum (oil) to produce electricity.

b. Fossil fuels are called so because they have been derived from fossils, which were formed millions of years ago during the time of the dinosaurs. They are fossilized organic remains that over millions of years have been converted to oil, gas, and coal.

C. they are generally classified as non-renewable resources because they take millions of years to form and known viable reserves are being depleted much faster than new ones are generated.

5.
a. Gravitational potential energy and work done
If an object is lifted, work is done against the force of gravity.
When work is done energy is transferred to the object and it gains gravitational potential energy.
If the object falls from that height, the same amount of work would have to be done by the force of gravity to bring it back to the Earth’s surface.
If an object at a certain height has 2000 J of gravitational potential energy, we can say that:
2000 J of work has been done in getting the object to that height from the ground
and
2000 J of work would have to be done to bring it back to the ground.
3 0
3 years ago
PLEASE HURRY
Sophie [7]

Decompose the forces acting on the block into components that are parallel and perpendicular to the ramp. (See attached free body diagram. Forces are not drawn to scale)

• The net force in the parallel direction is

∑ <em>F</em> (para) = -<em>mg</em> sin(21°) - <em>f</em> = <em>ma</em>

• The net force in the perpendicular direction is

∑ <em>F</em> (perp) = <em>n</em> - <em>mg</em> cos(21°) = 0

Solving the second equation for <em>n</em> gives

<em>n</em> = <em>mg</em> cos(21°)

<em>n</em> = (0.200 kg) (9.80 m/s²) cos(21°)

<em>n</em> ≈ 1.83 N

Then the magnitude of friction is

<em>f</em> = <em>µn</em>

<em>f</em> = 0.25 (1.83 N)

<em>f</em> ≈ 0.457 N

Solve for the acceleration <em>a</em> :

-<em>mg</em> sin(21°) - <em>f</em> = <em>ma</em>

<em>a</em> = (-0.457N - (0.200 kg) (9.80 m/s²) sin(21°))/(0.200 kg)

<em>a</em> ≈ -5.80 m/s²

so the block is decelerating with magnitude

<em>a</em> = 5.80 m/s²

down the ramp.

5 0
3 years ago
if a ball is rolling at a velocity of 1.5 m/sec and has the momentum of 10.0 kg m/sec, what is the mass of the ball?
PolarNik [594]
Okay. There is a simple formula to go with this where:

p = mv

P: Momentum.
M: Mass.
V: Velocity

Sub the numbers in and solve for M.

10.0 = m(1.5)
10.0/1.5 = m
6.67 kg = m

Therefore the mass of the ball is 6.67kg.
6 0
3 years ago
What is ham, I'm totally serious?
Sergeeva-Olga [200]
Ham is meat made from a pig =]
3 0
3 years ago
Read 2 more answers
Physics 10
Dominik [7]

Answer:

Option D (N/A-m)(m)(m/s)

Explanation:

(N/A-m)(m)(m/s) is the required dimensional analysis for calculation of emi

3 0
2 years ago
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