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Nimfa-mama [501]
3 years ago
11

How does a speedometer and odometer work?

Physics
1 answer:
valentinak56 [21]3 years ago
6 0
Speedometer tells you how fast your going and odometer is how many miles u drive
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Which of the following describes an ionic compound (or what is true for ionic compounds)?
mezya [45]

Answer:

a b c

Explanation:

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4 years ago
A 7450 kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.25 m/s2 and feels no appreci
sashaice [31]

Answer:

a) 112.5 m

b) 15.81s

Explanation:

a)We can use the following equation of motion to calculate the velocity v of the rocket at s = 500 m at a constant acceleration of a = 2.25 m/s2

v^2 = 2as

v^2 = 2*2.25*500 = 2250

v = \sqrt{2250} = 47.4 m/s

After the engine failure, the rocket is subjected to a constant deceleration of g = -10 m/s2 until it reaches its maximum height where speed is 0. Again if we use the same equation of motion we can calculate the vertical distance h traveled by the rocket after engine failure

0^2 - v^2 = 2gh

-2250 = 2(-10)h

h = 2250/20 = 112.5 m

So the maximum height that the rocket could reach is 112.5 + 500 = 612.5 m

b) Using ground as base 0 reference, we have the following equation of motion in term of time when the rocket loses its engine:

s + vt + gt^2/2 = 0

500 + 47.4t - 10t^2/2 = 0

5t^2 - 47.4t - 500 = 0

t= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

t= \frac{47.4\pm \sqrt{(-47.4)^2 - 4*(5)*(-500)}}{2*(5)}

t= \frac{47.4\pm110.67}{10}

t = 15.81 or t = -6.33

Since t can only be positive we will pick t = 15.81s

7 0
4 years ago
Read 2 more answers
A. Describe something that you do on a regular basis where friction slows you down (Use a different example than the ones in the
Scrat [10]

Answer:

i get good unlike you

Explanation:

its pretty simple to be honest

3 0
2 years ago
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What is the formula for Kepler’s 3rd law of planetary motion?
Stels [109]
The answer is C   Thank you!!!

6 0
3 years ago
A ball is thrown straight up from the ground with speed v0. At the same instant, a second ball is dropped from rest from a heigh
Kazeer [188]

Answer:

a)t = H/v_0

b)H = v_0^2/g

Explanation:

Let the first ball throw be the point of reference, we can have following the equation of motion:

1st ball: h_1 = v_0t - gt^2/2

2nd ball: h_2 = H - gt^2/2

a)When the 2 balls collide they are at the same spot at the same time:

h_1 = h_2

v_0t - gt^2/2 = H - gt^2/2

v_0t = H

t = H/v_0

b) The first ball is at its highest point when v = 0. That is

t = v_0/g

After this time, the 2 balls would have traveled through a distance of

h_1 = v_0t - gt^2/2 = v_0^2/g - v_0^2/2g

h_2 = gt^2/2 = v_0^2/2g

SinceH = h_1 + h_2 we can solve for H

H = v_0^2/g - v_0^2/2g + v_0^2/2g = v_0^2/g

3 0
3 years ago
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