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enot [183]
3 years ago
15

Write the equation for the quadratic function in standard form

Mathematics
1 answer:
Alina [70]3 years ago
8 0
Y=ax²+bx+c
c is x-int =7 (0,7), so c=7
vertex=(-3,-2),  another point (-6,7)
y=ax²+bx+7

-2=a(-3)²+b*(-3)+7,   -2=9a-3b+7,  ----> -9=9a-3b ---->-3=3a-b
7=a*(-6)²+b(-6)+7,  ---> 0=36a-6b, ---> 0=6a-b

-3=3a-b
0=6a-b ----> b=6a

substitute b=6a in -3=3a-b, so
-3=3a-6a, ----> -3= -3a,   a=1

substitute   a=1, in  b=6a, ---> b=6*1=6

y=ax²+bx+c
y=x²+6x+7






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