
![\qquad \tt \rightarrow \:Domain = [-9, -1]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3ADomain%20%3D%20%5B-9%2C%20-1%5D)
![\qquad \tt \rightarrow \:Range = [-1 , 3]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3ARange%20%3D%20%5B-1%20%2C%203%5D)
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Domain = All possible values of x for which f(x) is defined
[ generally the extension of function in x - direction ]
Range = All possible values of f(x)
[ generally the extension of function in y - direction ]

![\qquad \tt \rightarrow \: domain = [ - 9, -1]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3A%20domain%20%3D%20%5B%20-%209%2C%20-1%5D)
![\qquad \tt \rightarrow \: range= [ -1,3]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3A%20range%3D%20%5B%20-1%2C3%5D)
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
There is a line and a parabola in the graph.
So, we will get the solution set from the point of intersection of both line and parabola.
Notice that the parabola and the line intersecting at two points E(1, 5) and C(-0.5,2).
So, the solution set is E(1, 5) and C(-0.5,2).
From the recursive rule

it follows that


and so on. Notice how the subscript on a on the right side and the coefficient multiplied by 13 add up to n (n - 2 + 2 = n; n - 3 + 3 = n; and so on). If we continue the pattern, we'll end up with

so that the explicit rule for the n-th term in the sequence is

<span>A) 3x+4y=17
B) -4x-3y=-18 Multiplying B) by .75
</span><span>B) -3x -2.25y= -13.5 then adding this to A
</span><span><span>A) 3x + 4y = 17</span>
1.75y = 3.5
y = 2
</span><span>
A) 3x + 4*2 = 17</span>
3x + 8 = 17
3x = 9
x = 3
(3,2)
84 units tall. If one inch is 12 units then seven inches is 84 units.