Segment NO is parallel to the segment KL.
Solution:
Given KLM is a triangle.
MN = NK and MO = OL
It clearly shows that NO is the mid-segment of ΔKLM.
By mid-segment theorem,
<em>The segment connecting two points of the triangle is parallel to the third side and is half of that side.</em>
⇒ NO || KL and
Therefore segment NO is parallel to the segment KL.
Answer: Bottom left corner
Angle DEC and Angle DEH
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Explanation:
I recommend opening your favorite paint program, and using different colors to mark on the drawing as I have done below (see attached image). Note how angle DEC is in red and angle DEH is in blue. The two angles are adjacent, meaning they share the same ray (in this case, ray ED) and they form a straight angle.
Because they form a straight angle, or straight line, this means the two angles are supplementary. Supplementary angles always add to 180.
