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Kipish [7]
3 years ago
6

What are the oxidation numbers for Zn(OH)4 ^2-

Chemistry
1 answer:
aliya0001 [1]3 years ago
6 0
Zn(OH)4= ; -2 = -4 + ?, Zn = +2 , the -4 is the charge on the 4 OH- ions. 

<span>NO3- + 6 H2O + 8 e- -------> NH3 + 9 OH- </span>
<span>( Zn + 4 OH- ----> Zh(OH)4= + 2e-) x 4 </span>
<span>7 OH- + NO3- + 4 Zn + 6 H2O -------> NH3 + 4 Zn(OH)4=</span>
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