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Oliga [24]
3 years ago
13

An example of a strong _____ agent important in biochemistry is _____. The redox potential for this molecule is _____. Please ch

oose the correct answer from the following choices
a. oxidizing; O2;
b. negative reducing; NADH;
c. positive oxidizing; NADH;
d. positive reducing; O2;
e. negative reducing; NADH;
Chemistry
1 answer:
valkas [14]3 years ago
6 0

Answer:

Option B - reducing; NADH; negative

explanation:

Nicotinamide adenine dinucleotide, or NADH, is a compound, that's more actively used in the transportation of electron chain. It's evident that produced and make use NADH than FADH2 in the process that brings about energy creation.

NADH carries electrons from one reaction to another. Its Cofactor is in two forms in cells: NAD+ accepts electron from other molecule and hence reduced as an oxidizing agent while NADH is formed by this reaction, which can be used to donate electrons because it's a reducing agent. The main function of NAD is to transfer these reactions.

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1. Calculate the average reaction rate expressed in moles H2 consumed per liter per second.
valentina_108 [34]

Answer:

1) 0.0025 mol/L.s.

2) 0.0025 mol/L.s.

Explanation:

  • For the reaction:

<em>H₂ + Cl₂ → 2HCl.</em>

<em></em>

<em>The average reaction rate = - Δ[H₂]/Δt = - Δ[Cl₂]/Δt = 1/2 Δ[HCl]/Δt</em>

<em></em>

<em>1. Calculate the average reaction rate expressed in moles H₂ consumed per liter per second.</em>

<em></em>

The average reaction rate expressed in moles H₂ consumed per liter per second = - Δ[H₂]/Δt = - (0.02 M - 0.03 M)/(4.0 s) = 0.0025 mol/L.s.

<em>2. Calculate the average reaction rate expressed in moles CI₂ consumed per liter per second.</em>

<em></em>

The average reaction rate expressed in moles Cl₂ consumed per liter per second = - Δ[Cl₂]/Δt = - (0.04 M - 0.05 M)/(4.0 s) = 0.0025 mol/L.s.

7 0
3 years ago
Which of the following is NOT an important physical property of matter?
IgorLugansk [536]
The best option is melting point 
4 0
4 years ago
Consider 55 mL of water (H2O) in a beaker and 55 mL of acetone |(CHs)2CO in an identical beaker under identical conditions Compl
Zepler [3.9K]

Answer:

1. more slowly than

2. larger than

3. weaker

Explanation:

Acetone molecules are bonded by very weak intermolecular forces when compared to that of the hydrogen bond between water molecules. This makes it very easy for acetone molecules to vaporize easily into its gaseous state, much more faster than water molecules (since the acetone molecules need a lesser amount of energy to break these bonds). Also, the boiling point of liquid acetone is much lower than that of water, meaning that it has a higher vapor pressure than that of water.

4 0
3 years ago
The virial equation of state is not recommended to be used for polar compounds (asymmetrical compounds with non- zero dipole mom
Pepsi [2]

Answer:

True

Explanation:

*For polar and associated substances, methods based on four should be used  four or more parameters, like analytical equation of state

*The term "analytical equation of state" implies that the function

It contains powers of v not greater than four.

*Most expressions are of the cubic type and are grouped into

the so-called cubic equations of state.

*Cubic EoS calls are very popular in simulation of

processes due to its robustness and its simple extension to mixtures.

*They are based on the van der Waals state equation of more than

100 years.

7 0
3 years ago
The compound known as butylated hydroxytoluene, abbreviated as BHT, contains carbon, hydrogen, and oxygen. A 2.001 g sample of B
Alborosie

<u>Answer:</u> The empirical formula for the given compound is C_{15}H_{24}O_1

<u>Explanation:</u>

The chemical equation for the combustion of compound having carbon, hydrogen, iron and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=5.995g

Mass of H_2O=1.963g

Mass of sample = 2.001 g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

  • <u>For calculating the mass of carbon:</u>

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 5.995 g of carbon dioxide, \frac{12}{44}\times 5.995=1.635g of carbon will be contained.

  • <u>For calculating the mass of hydrogen:</u>

In 18g of water, 2 g of hydrogen is contained.

So, in 1.963 g of water, \frac{2}{18}\times 1.963=0.218g of hydrogen will be contained.

Mass of oxygen in the compound = (2.001) - (1.635 + 0.218) = 0.148 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon = \frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.635g}{12g/mole}=0.136moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.218g}{1g/mole}=0.218moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.148g}{16g/mole}=0.0092moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0092 moles.

For Carbon = \frac{0.136}{0.0092}=14.78\approx 15

For Hydrogen = \frac{0.218}{0.0092}=23.69\approx 24

For Oxygen = \frac{0.0092}{0.0092}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 15 : 24 : 1

Hence, the empirical formula for the given compound is C_{15}H_{24}O_1

3 0
4 years ago
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