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pishuonlain [190]
3 years ago
6

A gas at constant volume has a pressure of 3.20 atm at 300. K. What will be the pressure of the gas at 290. K?

Chemistry
1 answer:
melomori [17]3 years ago
3 0
  • From the general law of gases: PV = nRT,

where P is the pressure (atm),

V is the volume (L),

n is the number of moles,

R is the general gas constant (8.314 L.atm/mol.K),

T is the temperature in Kelvin

  • at constant volume of the gas: P1T2 = P2T1

P1 = 3.20 atm, T1 = 300 K, T2 = 290 K, P2 = ??

(3.20 atm)(290 K) = P2(300 K)

P2 = (3.20 atm)(290 K)/ (300 K) = 3.093 atm

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Answer:

Explanation:

Your strategy here will be to

use the chemical formula of carbon dioxide to find the number of molecules of

CO

2

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use Avogadro's constant to convert the number of molecules to moles of carbon dioxide

use the molar mass of carbon dioxide to convert the moles to grams

So, you know that one molecule of carbon dioxide contains

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⋅

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⋅

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2

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=

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⋅

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molecules CO

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Now, one mole of any molecular substance contains exactly

6.022

⋅

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In your case, the sample of carbon dioxide molecules contains

2.4

⋅

10

22

molecules CO

2

⋅

1 mole CO

2

6.022

⋅

10

23

molecules CO

2

=

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−

1

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0.03985

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⋅

44.01 g

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¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

∣

∣

a

a

1.8 g

a

a

∣

∣

−−−−−−−−−

The answer is rounded to two sig figs, the number of sig figs you have for the number of atoms of oxygen present in the sample.

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