Note that we are omitting the water.
So, sodium carbonate will basically dissociate into positive sodium ions and negative carbonate ions based on the following equation:
<span>Na2CO3 → 2 Na(+) + CO3(2-)
</span>
If we took water into consideration:
Sodium carbonate will dissociate in water forming carbonic acid and sodium hydroxide. Since sodium hydroxide is a strong base, therefore, it will then neutralize the gastric acid, thus, acting as an antacid.
We can tell which acid which have the highest percent ionization on the basis of pH value.
<h3>What is percent ionization?</h3>
The % ionized indicates how much of the original chemical has ionized. As a result, we compare the ion concentration in solution to the neutral species' original concentration.
If any acid have a high pH value then they must show high percent ionization because they are strong in nature and show full dissociation.
Hence acids with high pH value will show highest percent ionization.
To know more about percent ionization, visit the below link:
brainly.com/question/3229194
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HI is strong acid, so:
[H+] = [HI]
[H+] = 6 × 10^-3 M
pH = -log[H+]
pH = -log(6 × 10^-3) = 2,22
:-) ;-)
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Answer:
2.25 M is the final concentration of hydroxide ions ions in the solution after the reaction has gone to completion.
Explanation:
Moles of NaOH = 
Molarity of the nitric acid solution = 0.250 M
Volume of the nitric solution = 0.150 L
Moles of nitric acid = n



According to reaction, 1 mole of nitric acid recats with 1 mole of NaOH, then 0.0375 moles of nitric acid will react with :
of NaOH
Moles of NaOH left unreacted in the solution =
= 0.375 mol - 0.0375 mol = 0.3375 mol

1 mole of sodium hydroxide gives 1 mol of sodium ions and 1 mole of hydroxide ions.
Then 0.3375 moles of NaOH will give :
of hydroxide ion
The molarity of hydroxide ion in solution ;

2.25 M is the final concentration of hydroxide ions ions in the solution after the reaction has gone to completion.