The type of radioactive emissions that have positive charges and weak penetrating power are alpha rays
Answer:
See figure 1
Explanation:
For this question, we have to remember that in the lewis structures all atoms must have<u> 8 electrons</u>. And each atom would have a different value of <u>valence electrons</u>:
Carbon => 4
Oxygen=> 6
Hydrogen=> 1
Additionally, for the <u>hybridizations</u> we have to remember that:
=> 4 single bonds
=> 1 double bond
=> 1 double bond
With this in mind, the formaldehyde and formic acid would have carbons and the ethanol an carbon.
Finally, for the oxidation state. We have to remember that <u>if we have more bonds with oxygen, we will have more oxidation</u>. Therefore, the carbon that has more oxidation is the one in the formic acid (we have several bonds with oxygen).
See figure 1
I hope it helps!
The solution has a concentration 20 mgr in each mL of the final solution.
To solve this problem, we need to know about concentration. The concentration formula can be defined as how much the mass per unit volume is. It can be written as
M = m/V
where M is concentration, m is mass of solute, V is the total volume of solution.
From the text we know that :
m = 10g
vsolvent = 45mL
vsolute = 5 mL
find the total volume (V)
V = vsolvent + vsolute
V = 45 + 5
V = 50mL
Then, find the concentration
M = m/V
M = 10gr / 50 mL
M = 1000 mgr / 50mL
M = 20 mgr / mL
Hence, the solution has a concentration 20 mgr in each mL of the final solution.
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Answer:
mass of that can be removed from air=6.7gram
Explanation:
when you get this type of question first write their balance equation.
First write the balance chemical reaction:
given mass of diiodine pentaoxide=15.9gram
molar mass of diiodine pentaoxide=333.8g/mol
mole of diiodine pentaoxide =15.9/333.8mol
mole of diiodine pentaoxide=0.0476mol
from the above balance equation it is clear that;
1 mole diiodine pentaoxide remove 5 mole of CO from air
0.0476 mole of diiodine pentaoxide will remove of CO from air
mole of CO that can be removed=0.238mol
mass of that can be removed from air=6.664gram
mass of that can be removed from air=6.7gram