Answer:
166 torr
Explanation:
Let’s call ethane Component 1 and propane Component 2.
According to Raoult’s Law,
![p_{1} = \chi_{1}p_{1}^{\circ}\\p_{2} = \chi_{2}p_{2}^{\circ}](https://tex.z-dn.net/?f=p_%7B1%7D%20%3D%20%5Cchi_%7B1%7Dp_%7B1%7D%5E%7B%5Ccirc%7D%5C%5Cp_%7B2%7D%20%3D%20%5Cchi_%7B2%7Dp_%7B2%7D%5E%7B%5Ccirc%7D)
where
p₁ and p₂ are the vapour pressures of the components above the solution
χ₁ and χ₂ are the mole fractions of the components
p₁° and p₂° are the vapour pressures of the pure components.
Data:
p₁° = 304 torr
p₂° = 27 torr
n₁ = n₂
1. Calculate the mole fraction of each component
χ₁ = n₁/(n₁ + n₂)
χ₁ = n₁/n₁ + n₁)
χ₁ = n₁/(2n₁)
χ₁ = ½
χ₁ = 0.0.5
χ₂ = 1- χ₁ = 1- 0.5 = 0.5
2. Calculate the vapour pressure of the mixture
![p_{1} = 0.5 \times \text{304 torr} = \text{ 152 torr}\\p_{2} = 0.5 \times \text{27 torr} = \text{ 13.5 torr}\\p_{\text{tot}} = p_{1} + p_{2} = \text{152 torr + 13.5 torr} = \textbf{166 torr}](https://tex.z-dn.net/?f=p_%7B1%7D%20%3D%200.5%20%5Ctimes%20%5Ctext%7B304%20torr%7D%20%3D%20%5Ctext%7B%20152%20torr%7D%5C%5Cp_%7B2%7D%20%3D%200.5%20%5Ctimes%20%5Ctext%7B27%20torr%7D%20%3D%20%5Ctext%7B%2013.5%20torr%7D%5C%5Cp_%7B%5Ctext%7Btot%7D%7D%20%3D%20p_%7B1%7D%20%2B%20p_%7B2%7D%20%3D%20%5Ctext%7B152%20torr%20%2B%2013.5%20torr%7D%20%3D%20%5Ctextbf%7B166%20torr%7D)
![\text{The vapour pressure above the solution is $\boxed{\textbf{166 torr}}$}](https://tex.z-dn.net/?f=%5Ctext%7BThe%20vapour%20pressure%20above%20the%20solution%20is%20%24%5Cboxed%7B%5Ctextbf%7B166%20torr%7D%7D%24%7D)
Amplitude is the awnser glad I could help you
The given question is incomplete. The complete question is as follows.
A 2.300×10−2 m solution of nacl in water is at 20.0∘c. the sample was created by dissolving a sample of nacl in water and then bringing the volume up to 1.000 l. it was determined that the volume of water needed to do this was 999.4 ml . the density of water at 20.0∘c is 0.9982 g/ml.
Calculate the molality of the salt solution.
Express your answer to four significant figures and include the appropriate units.
Explanation:
Molality is defined as the number of moles present in kg of a solvent.
Mathematically, Molality = ![\frac{\text{moles of solute}}{\text{mass of solvent}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7Bmoles%20of%20solute%7D%7D%7B%5Ctext%7Bmass%20of%20solvent%7D%7D)
Also,
Mole of solute = Molarity of solute x Volume of solution
= (0.0230 M) x (1.000 L) = 0.0230 mol of solute
Therefore, mass of solvent will be as follows.
= 997.7 g
= 0.9977 kg (as 1 kg = 1000 g)
Therefore, we will calculate the molality as follows.
Molality =
= 0.02306 mol/kg
thus, we can conclude that molality of the given solution is 0.02306 mol/kg.
B
A mixture can be separated by a physical means because there is no chemical bond between the constituents
Answer:
Kinetic Energy
Explanation:
Kinetic energy is the energy inside moving objects of things.