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3 years ago

7

A 22.6 gram sample of krypton gas has a volume of 904 milliliters at a pressure of 2.71 atm. The temperature of the Kr gas sampl

e is:_____

1 answer:

Marrrta [24]3 years ago

5 0

Answer:

110.78 K

Explanation:

First we <u>convert 22.6 g of krypton gas (Kr) to moles</u>, using its <em>molar mass</em>:

22.6 g Kr ÷ 83.798 g/mol = 0.270 mol Kr

Then we use the PV=nRT formula, where:

P = 2.71 atm

V = 904 mL ⇒ 904/1000 = 0.904 L

n = 0.270 mol

R = 0.082 atm·L·mol⁻¹·K⁻¹

T = ?

2.71 atm * 0.904 L = 0.270 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * T

And <u>solve for T</u>:

T = 110.78 K

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