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lana66690 [7]
4 years ago
9

I tried looking at formulas, if you know the formula can you list it?

Physics
2 answers:
mash [69]4 years ago
8 0

Answer:

a. -10 m/s²

b. -15000 N

Explanation:

a. First, write which variables are given:

v₀ = 20 m/s

v = 0 m/s

t = 2 s

Next, identify the variable you're looking for.

Find: a

Determine which equation uses these variables.  One trick is to find which variable isn't included in the problem, then find the equation that doesn't use that variable.  In this case, we don't need displacement Δx.  So the equation we should use is:

v = at + v₀

Plug in and solve:

(0 m/s) = a (2 s) + (20 m/s)

a = -10 m/s²

b. Force is mass times acceleration.

F = ma

F = (1500 kg) (-10 m/s²)

F = -15000 N

serg [7]4 years ago
5 0

Answer:y=mx+b

Explanation:

y=mx+b

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The law of conservation of momentum states that __________.
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Why don't atoms get too close?
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Therefore; making force the subject;

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Two guitarists attempt to play the same note of wavelength 6.50 cm at the same time, but one of the instruments is slightly out
PolarNik [594]

Answer:

The two value of the wavelength for the out of tune guitar is  

\lambda _2 = (6.48,6.52) \ cm

Explanation:

From the question we are told that

     The wavelength of the note is \lambda  =  6.50 \ cm = 0.065 \ m

     The difference in beat frequency is \Delta  f = 17.0 \ Hz

     

Generally the frequency of the note played by the guitar that is in tune is  

        f_1 = \frac{v_s}{\lambda}

Where v_s is the speed of sound with a constant value v_s  =  343 \ m/s

       f_1 = \frac{343}{0.0065}

      f_1 = 5276.9 \ Hz

The difference in beat is mathematically represented as

       \Delta  f =  |f_1 - f_2|

Where f_2 is the frequency of the sound from the out of tune guitar

     f_2 =f_1  \pm \Delta f

substituting values

      f_2 =f_1 + \Delta f

      f_2 = 5276.9 + 17.0  

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The wavelength for this frequency is

      \lambda_2 = \frac{343 }{5293.9}

     \lambda_2 = 0.0648 \ m

    \lambda_2 = 6.48 \ cm

For the second value of the second frequency

     f_2 =  f_1 - \Delta f

     f_2 = 5276.9 -17

      f_2 = 5259.9 Hz

The wavelength for this frequency is

   \lambda _2 = \frac{343}{5259.9}

   \lambda _2 = 0.0652 \ m

   \lambda _2 = 6.52 \ cm

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