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lana66690 [7]
3 years ago
9

I tried looking at formulas, if you know the formula can you list it?

Physics
2 answers:
mash [69]3 years ago
8 0

Answer:

a. -10 m/s²

b. -15000 N

Explanation:

a. First, write which variables are given:

v₀ = 20 m/s

v = 0 m/s

t = 2 s

Next, identify the variable you're looking for.

Find: a

Determine which equation uses these variables.  One trick is to find which variable isn't included in the problem, then find the equation that doesn't use that variable.  In this case, we don't need displacement Δx.  So the equation we should use is:

v = at + v₀

Plug in and solve:

(0 m/s) = a (2 s) + (20 m/s)

a = -10 m/s²

b. Force is mass times acceleration.

F = ma

F = (1500 kg) (-10 m/s²)

F = -15000 N

serg [7]3 years ago
5 0

Answer:y=mx+b

Explanation:

y=mx+b

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Two carts, A and B, are connected by a spring and sitting at rest on a track. Cart A has a mass of 0.4 kg and Cart B has a mass
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Both carts experience the same force but Cart A has a greater speed after the recoil.

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Apply the principle of conservation of linear momentum to determine the velocity of the carts after collision;

m_Av_0_A\ + m_Bv_0_B = m_Av_f_A \ + m_Bv_f_B\\\\the \ initial \ velocity \ of \ both \ carts = 0\\\\0.4(0) + 0.8(0) = 0.4v_f_A + 0.8v_f_B\\\\0 = 0.4v_f_A + 0.8v_f_B\\\\0.4v_f_A = -0.8v_f_B\\\\v_f_A= \frac{-0.8 v_f_B}{0.4} \\\\v_f_A = - 2 \ v_f_B \ \ m/s

According to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart A is equal to the force exerted on cart B but in opposite direction.

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Thus, the correct statement that compares the motion and forces acting on the two carts is "Both carts experience the same force but Cart A has a greater speed after the recoil."

Learn more about conservation of linear momentum here: brainly.com/question/7538238

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