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3 years ago

All objects emit what radiation

Physics

1 answer:

Eduardwww [97]3 years ago

5 0

If an object is not at Absolute Zero, then it is
absorbing and radiating thermal (heat) energy.

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Identify the areas on the image where the force of repulsion is the least.

aalyn [17]

Answer:

The central blue square in between the lower pair of magnet has the least force of repulsion.

Explanation:

We can explain this using the dual nature of magnets.

Each magnet must have two poles namely:

-North pole

-South pole

We assume that the magnetic lines of forces enters from south pole and leaves from the north pole.

When brought together, like poles repel each other while opposite poles attract each other.

In the picture, the lower two magnets have opposite poles facing each other, hence the force of repulsion is minimum there and the force of attraction is maximum.

4 0

3 years ago

Read 2 more answers

Object A attracts object B with a gravitational force of 5 newtons from a given distance. If the distance between the two object

enyata [817]

Answer:

10 newtons, because the gravitaional force willbe stronger the closer it gets.

7 0

3 years ago

Please send me solution of the question pls

ELEN [110]

Answer:

20m

Explanation:

P.E=mgh

2000=10×10×h

2000=100h

Divide both side by 100

2000/100=20

4 0

3 years ago

What frequency (in Hz) is received by a person watching an oncoming ambulance moving at 116 km/h and emitting a steady 950 Hz so

Arte-miy333 [17]

To solve this problem we will apply the concepts related to the Doppler Effect, defined as the change in apparent frequency of a wave produced by the relative movement of the source with respect to its observer. Mathematically it can be written as

$f_{obs} = f(\frac{v_w}{v_w-v_s})$

Here,

$f_s$ = Frequency of the source

$v_w$ = Speed of the sound

$v_s$ = Speed of source

Now the velocity we have that

$v_s = 116km/h (\frac{1000m}{1km})(\frac{1h}{3600s})$

$v_s = 32.22m/s$

Then replacing our values,

$f_{obs} = (950Hz) (\frac{345m/s}{345m/s-32.22m/s})$

$f_{obs} = 1047.86Hz$

Therefore the frequency of the observer is 1047.86Hz

8 0

3 years ago

A ball travels with velocity given by Error converting from MathML to accessible text., with wind blowing in the direction given

KengaRu [80]

Answer: The magnitude of the velocity = 2/5 m/s

Explanation:

In this question, the magnitude of the velocity is the product of the magnitude of the displacement vector and the magnitude of the component of the velocity that acts in the direction of displacement.

This will be a scalar projection of V onto X

Please find the attached files for the solution

5 0

3 years ago