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2 years ago

12

All objects emit what radiation

1 answer:

Eduardwww [97]2 years ago

5 0

If an object is not at Absolute Zero, then it is
absorbing and radiating thermal (heat) energy.

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A boy drops a 0.10 kg stone down a 150 m well and listens for the echo. The air temperature is 20°C. How long after the stone is

S_A_V [24]

Use formula for Echo which is Velocity=2(Distance)/time so 343=2(150)/T 343T=300..T=300/343=0.9 seconds

4 0

2 years ago

An ac voltage, whose peak value is 250 V , is across a 330-Ω resistor. Part A What is the peak current in the resistor?

Wittaler [7]

Answer:

Peak current is 0.75 A

RMS voltage is 176.77 V

RMS current is 0.53 A

Explanation:

Peak current is

$I=\frac{V}{R} \\\\I=\frac{250}{330}\\I=0.75 A$

RMS voltage is

$V_{RMS}=\frac{V}{\sqrt{2} } \\V_{RMS}=\frac{250}{\sqrt{2} }\\V_{RMS}=176.77 V$

RMS current is

$I_{RMS}=\frac{V_{RMS}}{R} \\I_{RMS}=\frac{176.77}{330} \\I_{RMS}=0.53 A$

7 0

3 years ago

A diffusion couple, made by welding a thin onecentimeter square slab of pure metal A to a similar slab of pure metal B, was give

bezimeni [28]

Answer:

The value is $H = 18*10^{2} \ Atom / sec$

Explanation:

From the question we are told that

The atom fraction of metal A at point G is $A = 0.30 \ m$

The atom fraction of metal A at a distance 5000nm from G is $A_2 = 0.35$

The number of atoms per $m^3$ is $N_h = 9 * 10^{28}$

The diffusion coefficient is $D = 2* 10^{-14 } m^2/s$

Generally of the concentration of atoms of metal A at G is

$N_A = A * N_h$

=> $N_A = 0.3 * 9 * 10^{28}$

=> $N_A = 2.7 * 10^{28} 2.7 atoms/m^3$

Generally of the concentration of atoms of metal A at a distance 5000nm from G is

$D = 0.35 *9 * 10^{28}$

=> $D = 3.15 * 10^{28} \ atoms / m^3$

The concentration gradient is mathematically represented as

$\frac{dN_A}{dx} = \frac{(3.15 - 2.7) * 10^{28} }{5000nm - 0 }$

=> $\frac{dN_A}{dx} = \frac{(3.15 - 2.7) * 10^{28} }{[5000 *10^{-9}] - 0 }$

=> $\frac{dN_A}{dx} = 9 * 10^{20} / m^4$

Generally the flux of the atoms per unit area according to Fick's Law is mathematically represented as

$J = -D* \frac{d N_A}{dx}$

=> $J = -2* 10^{-14 * 9 * 10^{20}$

=> $J = 18*10^{6}\ atoms\ crossing\ /m^2 s$

Generally if the cross-section area is $a = 1 cm^2 = 10^{-4} \ m^2$

Generally the number of atom crossing the above area per second is mathematically is

$H = 18*10^{6} * 10^{-4}$

=> $H = 18*10^{2} \ Atom / sec$

7 0

3 years ago

Check out this app! It's millions of students helping each other get through their schoolwork. what Is Fandamental

lorasvet [3.4K]

Answer:

cool ig

Explanation:

6 0

2 years ago

Read 2 more answers

A standard light bulb emits light rays in _________ directions.

Ainat [17]

Omni-directional. It means all directional.

4 0

2 years ago