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aliya0001 [1]
3 years ago
5

A bowl contains 80 M&M candies. If 15 of the candies are orange, what fraction of the candies is not orange?

Mathematics
2 answers:
lesantik [10]3 years ago
5 0
65 candies are not orange.
trasher [3.6K]3 years ago
5 0
So there are 80 M&M candies. So that's the total, which is called the denominator in fraction. Now 15 of them are orange, so if we had a fraction bar out of 15, we would shade in 15. Now the amount that is left over is 65 M&M candies, which are going to be the numerator.

Answer : 65/80 candies are not orange.

Hope that Helped :)


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zalisa [80]
We have that
A(-2,-4)  B(8,1) <span>

let
M-------> </span><span>the coordinate that divides the directed line segment from A to B in the ratio of 2 to 3

we know that

A--------------M----------------------B
        2                     3
distance AM is equal to (2/5) AB
</span>distance MB is equal to (3/5) AB
<span>so

step 1
find the x coordinate of point M
Mx=Ax+(2/5)*dABx
where
Mx is the x coordinate of point M
Ax is the x coordinate of point A
dABx is the distance AB in the x coordinate
Ax=-2
dABx=(8+2)=10
</span>Mx=-2+(2/5)*10-----> Mx=2

step 2
find the y coordinate of point M
My=Ay+(2/5)*dABy
where
My is the y coordinate of point M
Ay is the y coordinate of point A
dABy is the distance AB in the y coordinate
Ay=-4
dABy=(1+4)=5
Mx=-4+(2/5)*5-----> My=-2

the coordinates of point M is (2,-2)

see the attached figure

7 0
3 years ago
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Brooks used 2/3 of a can of paint to paint the bird feeder. A full can of paint contains 7/8 of a gallon. How much paint did Bro
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4 0
3 years ago
Read 2 more answers
Show that 3 · 4^n + 51 is divisible by 3 and 9 for all positive integers n.
-BARSIC- [3]

Answer:

Step-by-step explanation:

Hello, please consider the following.

3\cdot 4^n+51=3\cdot 4^n+3\cdot 17=3(4^n+17)

So this is divisible by 3.

Now, to prove that this is divisible by 9 = 3*3 we need to prove that

4^n+17 is divisible by 3. We will prove it by induction.

Step 1 - for n = 1

4+17=21= 3*7 this is true

Step 2 - we assume this is true for k so 4^k+17 is divisible by 3

and we check what happens for k+1

4^{k+1}+17=4\cdot 4^k+17=3\cdot 4^k + 4^k+17

3\cdot 4^k is divisible by 3 and

4^k+17 is divisible by 3, by induction hypothesis

So, the sum is divisible by 3.

Step 3 - Conclusion

We just prove that 4^n+17 is divisible by 3 for all positive integers n.

Thanks

4 0
3 years ago
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