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aliya0001 [1]
3 years ago
5

A bowl contains 80 M&M candies. If 15 of the candies are orange, what fraction of the candies is not orange?

Mathematics
2 answers:
lesantik [10]3 years ago
5 0
65 candies are not orange.
trasher [3.6K]3 years ago
5 0
So there are 80 M&M candies. So that's the total, which is called the denominator in fraction. Now 15 of them are orange, so if we had a fraction bar out of 15, we would shade in 15. Now the amount that is left over is 65 M&M candies, which are going to be the numerator.

Answer : 65/80 candies are not orange.

Hope that Helped :)


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Two fair dice, one yellow and one blue, are rolled. The value of the blue die is subtracted from the value of the yellow die. Wh
mario62 [17]

Answer:

B) symmetric

Step-by-step explanation:

We will find the sample space for rolling two dices first

Here first value in ordered pair represents yellow die and second represents blue die

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)

The subtraction gives us:

0 , -1 , -2, -3, -4, -5, 1, 0, -1, -2, -3, -4, 2, 1, 0, -1, -2, -3, 3, 2, 1, 0, -1, -2, 4, 3, 2, 1, 0, -2, 5, 4, 3, 2, 1, 0

So the distribution will be as follows:

X      5       4       3       2        1        0        -1       -2      -3       -4      -5

P(X)  1/36  2/36  3/36 4/36  5/36  6/36  5/36  4/36  3/36  2/36  1/36

By observing the probabilities, we can conclude that the distribution will be symmetric

Hence, Option B is correct ..

4 0
3 years ago
Read 2 more answers
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