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3 years ago

Select the name of the element with a condensed ground-state electron configuration of [kr] 5s14d7.

Chemistry

2 answers:

Vilka [71]3 years ago

7 0

elements have equal number of protons and neutrons

the condensed format is when the closest noble gas with the closest electron configuration is given, this closest noble gas atomic number should be lesser than the atoms atomic number

atomic number of Kr is 36

1 electron in 5s subshell and 7 electrons in 4d subshell.

there's a total of 36 + 1 + 7 = 44 electrons

atomic number of the atom is 44

element with atomic number 44 is Ruthenium - Ru

answer is Ru

Tju [1.3M]3 years ago

3 0

Should be rhodium. hope that helps

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How do you write 400000 in scientific notation?

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Answer:

4 x 10 5

Explanation:

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3 years ago

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Helium is the lightest noble gas and the second most abundant element (after hydrogen) in the universe. The mass of a helium−4 a

dmitriy555 [2]

<u>Answer:</u> The fraction of atom's mass contributed by nucleus is 0.99

<u>Explanation:</u>

Nucleons are defined as the sub-atomic particles which are present in the nucleus of an atom. Nucleons are protons and neutrons.

The isotopic symbol of Helium-4 atom is $_2^4\textrm{He}$

Number of electrons = 2

Number of protons = 2

Number of neutrons = 4 - 2 = 2

We are given:

Mass of He-4 atom = $6.64648\times 10^{-24}g$

Mass of 1 electron = $9.10939\times 10^{-28}g$

Calculating the mass contributed by the nucleus = $m_{He}-2(m_e)$

Mass of the nucleus of He-4 atom = $6.64648\times 10^{-24}-(2\times (9.10939\times 10^{-28}))=(6.64648-0.0018219)\times 10^{-24}=6.64466\times 10^{-24}$

To calculate the fraction of atom's mass contributed by the nucleus, we use the equation:

$\text{Fraction of atom's mass contributed by nucleus}=\frac{\text{Mass of nucleus}}{\text{Mass of atom}}$

Putting values in above equation, we get:

$\text{Fraction of atom's mass contributed by nucleus}=\frac{6.64466\times 10^{-24}g}{6.64648\times 10^{-24}g}=0.99$

Hence, the fraction of atom's mass contributed by nucleus is 0.99

8 0

3 years ago

How many moles of HCL are needed to react with 0.300 mol of na2 CO3

Morgarella [4.7K]

Answer:

(b) Calculate the molarity of a solution of 4.8 mole of HCl in 600 mL of solution. ... (g) Calculate the mass of Na2CO3 that must be used to make 700 mL of a 0.136 M Na2CO3 ... (h) What mass of NaOH is needed to make 200 mL of a 0.300 M NaOH solution? ... However, when we are reacting solutions we have to convert.

Explanation:

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2 years ago

The Bohr model of the Adam addressed the problem of

Sati [7]

It addressed the problem concerning why electrons didn't fall into the positive nucleus. HOPE THIS HELPS BRAINLIEST PLEASE

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3 years ago

Calculate the vapor pressure of a solution of 32.5 g of glycerol (C3H8O3) in 500.0 g of water at 25°C. The vapor pressure of wat

Luba_88 [7]

The vapor pressure is obtained as 23.47 torr.

<h3>What is the vapor pressure?</h3>

Given that; p = x1p°

p = vapor pressure of the solution

x1 = mole fraction of the solvent

p° = vapor pressure of the pure solvent

Δp = p°(1 - x1)

Δp =x2p°

Δp = vapor pressure lowering

x2 = mole fraction of the of the solute

Number of moles of glycerol = 32.5 g/92 g/mol = 0.35 moles

Number of moles of water = 500.0 g/18 g/mol = 27.8 moles

Total number of moles = 0.35 moles + 27.8 moles = 28.15 moles

Mole fraction of glycerol = 0.35 moles/28.15 moles = 0.012

Mole fraction of water = 27.8 moles/28.15 moles =0.99

Δp = 0.012 * 23.76 torr

Δp = 0.285 torr

p1 = p° - Δp

p1 = 23.76 torr - 0.285 torr

p1 = 23.47 torr

Learn more about vapor pressure:brainly.com/question/14718830

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2 years ago