Answer:
The answer is nitric acid
Explanation:
Hope this helped Mark BRAINLIEST!!!
Answer:
Part A = The mass of sulfur is 6.228 grams
Part B = The mass of 1 silver atom is 1.79 * 10^-22 grams
Explanation:
Part A
Step 1: Data given
A mixture of carbon and sulfur has a mass of 9.0 g
Mass of the product = 27.1 grams
X = mass carbon
Y = mass sulfur
x + y = 9.0 grams
x = 9.0 - y
x(molar mass CO2/atomic mass C) + y(molar mass SO2/atomic mass S) = 22.6
(9 - y)*(44.01/12.01) + y(64.07/32.07)
(9-y)(3.664) + y(1.998)
32.976 - 3.664y + 1.998y = 22.6
-1.666y = -10.376
y = 6.228 = mass sulfur
x = 9.0 - 6.228 = 2.772 grams = mass C
The mass of sulfur is 6.228 grams
Part B
Calculate the mass, in grams, of a single silver atom (mAg = 107.87 amu ).
Calculate moles of 1 silver atom
Moles = 1/ 6.022*10^23
Moles = 1.66*10^-24 moles
Mass = moles * molar mass
Mass = 1.66*10 ^-24 moles *107.87
Mass = 1.79 * 10^-22 grams
The mass of 1 silver atom is 1.79 * 10^-22 grams
C=Carbon
O=Oxygen
Oxygen is a diatomic molecule, so the subscript two needs to be used after the O in the formula.
C+O2->CO2
Hope this helps!
Answer: 0.17M
Explanation:
The equation for the reaction is :
2HNO3 + Ba(OH)2 —> Ba(NO3)2 + 2H2O
From the balanced equation, we obtain :
nA = mole of acid = 2
nB = mole of the base = 1
From the question, we obtain:
Va = Vol. Of acid = 0.105L
Ma = conc. Of acid =?
Vb = Vol of base = 35.7 mL = 0.0357L
Mb = conc. of base = 0.25M.
We solve for the conc. of the acid using:
MaVa / Mb Vb = nA / nB
(Ma x 0.105) / (0.25x0.0357) = 2
Cross multiply to express in linear form. We have:
Ma x 0.105 = 0.25 x 0.0357 x 2
Divide both side by 0.105. We have
Ma = (0.25 x 0.0357 x 2) / 0.105
Ma = 0.17M
Therefore the concentration of the acid(HNO3) is 0.17M
If a substance is not chemically pure, it is either a heterogeneous mixture or a homogeneous mixture. If its composition is uniform throughout, it is a homogeneous mixture.
