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pentagon [3]
3 years ago
7

What is the smallest unit of an element that shares the element’s properties?

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
6 0
........it's atom....
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Alkenes can be converted to alcohols by hydroboration‑oxidation. Draw the structure of the alcohol or alcohols formed in the rea
OLEGan [10]

Hydroboration-oxidation is a reaction which follow anti markonikov orientation.

The stereochemistry of hydroboration-oxidation follows syn-adition being a stereospecific reaction. That means that boron and hydrogen are added from the same side.  Then, when the oxidation occurs, the boron is replaced by an hydroxyl having the same geometric position.

6 0
3 years ago
How many moles of water are needed in order to produce 218 g of calcium
ella [17]

Answer:

-------> CH2 + Ca(OH)2

0.59 moles

111 moles

30 moles

0.15 moles

3 0
3 years ago
2.2.<br> Name the two stages of photosynthesis
andre [41]

Answer:

1. Light-dependent stage

2. Light-independent stage or Calvin cycle

Explanation:

Photosynthesis is the process by which plants and other autotrophic organisms synthesize their food (glucose) in the presence of sunlight as energy source. However, this photosynthetic process, which is a metabolic reaction occurs in two stages namely; Light-dependent stage and Light-independent stage.

- The light dependent stage occurs in the thylakoid membrane of the chloroplast. It involves the synthesis of NADPH and ATP needed for the light independent stage of photosynthesis.

- The light independent stage also known as Calvin cycle occurs in the stroma of the chloroplast. This is the stage where glucose is synthesized using inorganic source of carbon (CO2).

6 0
4 years ago
If 12.1 kilograms of al2o3(s), 60.4 kilograms of naoh(l), and 60.4 kilograms of hf(g) react completely, how many kilograms of cr
Fynjy0 [20]
Answer is: 7,826 kg of cryolite.
Chemical reaction: Al₂O₃ + 6NaOH + 12HF → 2Na₃AlF₆ + 9H₂<span>O.
m(</span>Al₂O₃) = 12,1 kg = 12100 g.
n(Al₂O₃) = m(Al₂O₃) ÷ M(Al₂O₃).
n(Al₂O₃) = 12100 g ÷ 101,96 g/mol = 111,86 mol; limiting reactant.
m(NaOH) = 60,4 kg = 60400 g.
n(NaOH) = 60400 g ÷ 40 g/mol.
n(NaOH) = 1510 mol.
m(HF) = 60,4 kg = 60400 g.
n(HF) = 60400 g ÷ 20 g/mol = 3020 mol.
From chemical reaction: n(Al₂O₃) : n(Na₃AlF₆) = 6 : 2.
n(Na₃AlF₆) = 2 ·111,86 mol ÷ 6 = 37,28 mol.
m(Na₃AlF₆) = 37,28 mol · 209,94 g/mol.
m(Na₃AlF₆) = 7826,56 g = 7,826 kg.
7 0
4 years ago
What mass of sodium hydroxide is needed to neutralise 24.5kg of sulfuric acid <br> H2SO4 + N2 = 2NH3
sveticcg [70]

Answer:

23.92 g

Explanation:

Molar mass of H2SO4 = (2×1)+32+(16×4)= 2+32+48= 82g/mol

H2SO4 + 2NaOH ---> Na2SO4 + 2H2O

I mole of H2SO4 = 2 moles of NaOH

24.5/82 = 24.5/82 × 2

= 0.598 moles of NaOH will neutralize

Mass= mole× molar mass

Molar mass of NaOH= 23+16+1 = 40g/mol

Mass= 0.598 × 40 = 23.92g of NaOH

7 0
3 years ago
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