Answer:
AICI3
one aluminum and three chlorine
Answer:
The Henry's law constant for argon is ![k=2.11*10^{-3}\frac{ M}{atm}](https://tex.z-dn.net/?f=k%3D2.11%2A10%5E%7B-3%7D%5Cfrac%7B%20M%7D%7Batm%7D)
Explanation:
Henry's Law indicates that the solubility of a gas in a liquid at a certain temperature is proportional to the partial pressure of the gas on the liquid.
C = k*P
where C is the solubility, P the partial pressure and k is the Henry constant.
So, being the concentration
where ngas is the number of moles of gas and V is the volume of the solution, you must calculate the number of moles ngas. This is determined by the Ideal Gas Law: P*V=n*R*T where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. So ![n=\frac{P*V}{R*T}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7BP%2AV%7D%7BR%2AT%7D)
In this case:
- P=PAr= 1 atm
- V=VAr= 5.16*10⁻² L
- R=0.082
![\frac{atm*L}{mol*K}](https://tex.z-dn.net/?f=%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D)
- T=25 °C=298 °K
Then:
![n=\frac{1 atm*5.16*10^{-2} L}{0.082 \frac{atm*L}{mol*K} *298K}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B1%20atm%2A5.16%2A10%5E%7B-2%7D%20L%7D%7B0.082%20%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D%20%2A298K%7D)
Solving:
n= 2.11 *10⁻³ moles
So: ![C=\frac{ngas}{V}=\frac{2.11*10^{-3} moles}{1 L} =2.11*10^{-3} \frac{moles}{L}= 2.11*10^{-3} M](https://tex.z-dn.net/?f=C%3D%5Cfrac%7Bngas%7D%7BV%7D%3D%5Cfrac%7B2.11%2A10%5E%7B-3%7D%20moles%7D%7B1%20L%7D%20%3D2.11%2A10%5E%7B-3%7D%20%5Cfrac%7Bmoles%7D%7BL%7D%3D%202.11%2A10%5E%7B-3%7D%20M)
Using Henry's Law and being C=CAr and P
=PAr:
2.11*10⁻³ M= k* 1 atm
Solving:
![k=\frac{2.11*10^{-3} M}{1 atm}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.11%2A10%5E%7B-3%7D%20M%7D%7B1%20atm%7D)
You get:
![k=2.11*10^{-3}\frac{ M}{atm}](https://tex.z-dn.net/?f=k%3D2.11%2A10%5E%7B-3%7D%5Cfrac%7B%20M%7D%7Batm%7D)
<u><em>The Henry's law constant for argon is </em></u>
<u><em></em></u>
The given compounds are alkanes. This means that the formula
is C_nH_2n+2
The general trend for boiling point in alkanes is that the
greater number of carbon atoms, the higher the boiling point. If the alkane is
branched, the branched alkane will have a higher boiling point than the
straight chain.
Taking these into account: propane < heptane <
triptane < hexadecane < paraffin
Answer:
moles of water in 1 ml = 1/18 mol.
take 1 ml and calculate it by 30
1 ml x 30= 30 ml
Explanation:
The hills and valleys decrease the height and speed of the ride. This means that the graph has a negative correlation.
By the way, I think you may have plotted your points incorrectly. The directions said to connect them all with a smooth line or curve.
Also, this is not high school chemistry. This is more likely to be elementary school science. Just make sure that you put your questions in the correct categories next time! :)