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ira [324]
3 years ago
8

Increasing temperature increases solubility so that 480 grams (g) of sugar makes a saturated solution in 100 milliliters (mL) of

boiling water. If you add 240 g of sugar to 50 mL of boiling water, which will the solution be?
resaturated
supersaturated
saturated
Chemistry
1 answer:
valkas [14]3 years ago
8 0
Solubility at 100 °C = 480 g / 100 mL of solution =: saturated solution

The proportion 240 g / 50 mL  is equal to the saturated ratio 480 g / 100 mL

Then, 240 g of sugar in 50 mL of boiling water will make a saturated solution.

Answer: saturated


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4.
Mila [183]

Answer:

0.47m²

Explanation:

Given parameters:

Length = 9.025 x 10⁶m

Width  = 5.215 x 10⁻⁸m

Unknown:

Area of the rectangle  = ?

Solution:

Area is the derived from the product of the length and width of a body.

 Area  = length x width  = 9.025 x 10⁶m  x  5.215 x 10⁻⁸m

  Area  = 0.47m²

6 0
3 years ago
Please Help!!<br> Qns 1b to 3
Gelneren [198K]

Answer: Ammonium, when heated with aqueous base, will give off NH3 (ammonia) gas, (and depending, water vapor). This will leave the Cr2O3(s). From then on,

it is just adding or subtraction of gases or water vapor. You probably heard “Loss of electrons is Oxidation”, “Gain of Electrons is reduction”. That should help.

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7 0
3 years ago
If 225 grams of propane are burned in the presence of 125 grams of oxygen, how many grams of water should be expected?
Travka [436]
150 grams of water because if 225 grams of propane are burned with 125 grams of oxyegen then there will be 150 grams of water

5 0
3 years ago
The arrows show the changes of state.
Romashka [77]

Answer:

condensation

Explanation:

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3 0
3 years ago
Draw the structure for cis-2,3-dibromo-2-hexene.
padilas [110]
First, draw the 2-hexene. Th is is a molecule of six carbons with a double bond in the second carbon:

      CH3 - CH = CH2 - CH2 - CH2 - CH3

Secong, put one Br on the second carbon and one Br on the third carbon:

    CH3 - CBr = CBr - CH2 - CH2 - CH3

Third, cis means that the two Br are placed in opposed positions, this is drawn with one Br up and the other down. So, you need to represent the position of the Br in the space:


      H   Br          H     H      H
       |    |             |       |       |
H - C - C = C -  C  -  C  -  C - H
       |           |      |       |       |
      H          Br   H     H      H

The important fact to realize is that the two Br are in opposed sides of the molecule.
4 0
3 years ago
Read 2 more answers
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