Increasing temperature increases solubility so that 480 grams (g) of sugar makes a saturated solution in 100 milliliters (mL) of
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CuCl2 is Dichloride Copper, or Copper II Chloride.
In this Molecule, there is 1 atom of Copper for every 2 atoms of Chlorine.
If you go to the periodic table, you'll see that copper has a mass of 63.5 amu, and the chlorine 35.45 amu.
Which mean that the mass of CuCl2 is 63.5 + 35.45*2 = 63.5 + 70.9 = 134.4 g/mol.
Then, you find the ration of the mass of each atom and multiply by 100.
Ratio of Copper:
and you get about 47.2%
Ration of chlorice (Cl2):
and you get about 52.8%.
So, the percent composition of CuCl2 is 47.2% of Copper and 52.8% of chlorine.
Hope this Helps :)
In this Molecule, there is 1 atom of Copper for every 2 atoms of Chlorine.
If you go to the periodic table, you'll see that copper has a mass of 63.5 amu, and the chlorine 35.45 amu.
Which mean that the mass of CuCl2 is 63.5 + 35.45*2 = 63.5 + 70.9 = 134.4 g/mol.
Then, you find the ration of the mass of each atom and multiply by 100.
Ratio of Copper:
Ration of chlorice (Cl2):
So, the percent composition of CuCl2 is 47.2% of Copper and 52.8% of chlorine.
Hope this Helps :)
<u>Answer:</u> The mass of hydrogen cyanide formed is 0.17 grams
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of KCN = 0.420 g
Molar mass of KCN = 65.12 g/mol
Putting values in equation 1, we get:
The given chemical equation follows:
As, hydrochloric acid is present in excess. So, it is considered as an excess reagent.
Thus, potassium cyanide is a limiting reagent because it limits the formation of products.
By Stoichiometry of the reaction:
1 mole of potassium cyanide produces 1 mole of hydrogen cyanide.
So, 0.0064 moles of potassium cyanide will produce = of hydrogen cyanide
Now, calculating the mass of hydrogen cyanide from equation 1, we get:
Molar mass of HCN = 27.02 g/mol
Moles of HCN = 0.0064 moles
Putting values in equation 1, we get:
Hence, the mass of hydrogen cyanide formed is 0.17 grams