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adelina 88 [10]
3 years ago
11

Adam wants to decrease his current weight, so he should?

Physics
2 answers:
Leona [35]3 years ago
6 0

Answer:

B. decrease his caloric intake so it is less than the calories he burns

Explanation:

A calorie is the amount of heat required to raise the temperature of a gram of water by 1°C.

Our bodies require a certain number of calories for us to sustain ourselves. However, if we consume more calories than we are using then this leads to the calories being stored in the form of glycogen or fat.

So, Adam needs to consume a lower number of calories so that he can burn the excess away.

irinina [24]3 years ago
3 0

Answer: B) decrease his caloric intake so it is less than the calories he burns

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What is the weight of a dust particle
Alexandra [31]

Answer:

The mass of a dust particle is 7.53 x 10^-10 kg. (Hope it helped.)

Explanation:

3 0
3 years ago
Which property of light is a constant in a vacuum?
faust18 [17]

Answer:

La velocidad de la luz en el vacío es una constante universal con el valor de 299 792 458 m/s (186 282,397 mi/s),​​aunque suele aproximarse a 3·108 m/s. Se simboliza con la letra c, proveniente del latín celéritās (en español, celeridad o rapidez).

¿Cuál es la consecuencia que a velocidad de la luz sea constante?

Respuesta. En modificaciones del vacío más sutiles, como espacios curvos, efecto Casimir, poblaciones térmicas o presencia de campos externos, la velocidad de la luz depende de la densidad de energía de ese vacío.

5 0
2 years ago
A car accelerate from 25m/s to 50m/s over a time of 10 second.what is acceleration of the car
Ann [662]
A=(vf-vi)/t
a=(50-25)/10
a=2.5m/s^2
5 0
3 years ago
What is the index of refraction of a material in which the speed of light is 7.50% slower than the speed of light in vacuum?
Inessa [10]

Answer:

The value is n = 1.081

Explanation:

From the question we are told that

   The speed of in a vacuum is c = 3.0 *10^{8} \  m/s

    The speed of light in the material is  v  =  c -0.075c = 0.925 c =  0.925 * 3.0*10^{8}  = 2.775 *10^{8} \ m/s

   Generally the reflection of the material is mathematically represented as

             n = \frac{c}{v}

=>    n = \frac{3.0*10^{8}}{2.775 *10^{8}}

=>    n = 1.081

8 0
3 years ago
Please please help me, don't guess please my test is timed !!
dimulka [17.4K]

Answer:

a) J = F  t = 40 * .05 = 2 N-s

b)  J = 2 N-s     momentum changed by 2 N-s

c) Initial momentum appears to be zero

J = change in momentum = m v2 - m v1 = m v2 = 2 N-s

v2 = J / m = 2 / .057 = 35 m/s

d) if the impulse time was increased and the average force remained the same then the change in momentum would increase with a corresponding increase in velocity attained - note the increase in v2 in part c)

4 0
2 years ago
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