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3 years ago

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A soccer ball was kicked . it had the mass of .42 kg and accelerated at 25m/s . what was the force?

1 answer:

kaheart [24]3 years ago

6 0

brainly.com/question/3414828
here lol

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An object has a kinetic energy ke, and potential energy pe. it also has a rest energy e0. what is the object's total energy e?

Dmitriy789 [7]

Look that one up in you text book PG:678 that is if you got the same book as my friend<span />

7 0

3 years ago

A square loop of side 7 cm is placed with the nearest side 2 cm from a long wire carrying a current that varies with time at a c

ioda

Answer:

Explanation:

side of the square loop, a = 7 cm

distance of the nearest side from long wire, r = 2 cm = 0.02 m

di/dt = 9 A/s

Integrate on both the sides

$\int _{0}^{i}di =9\int _{0}^{t}dt$

i = 9t

(a) The magnetic field due to the current carrying wire at a distance r is given by

$B = \frac{\mu_{0}i}{2\pi r}$

$B = \frac{\mu_{0}\times 9t}{2\pi r}$

(b)

Magnetic flux,

$\phi=\int B\times a dr$

$\phi=\int \frac{\mu_{0}\times 9t}{2\pi r}\times a dr$

$\phi=\frac{\mu_{0}\times 9t\times a}{2\pi}\times ln\left ( \frac{2 + 7}{2} \right )$

$\phi=\frac{\mu_{0}\times 9t\times 0.07}{2\pi}\times ln(4.5)$

$\phi = 1.89 \times 10^{-7}t$

(c)

R = 3 ohm

$e = -\frac{d\phi}{dt}$

magnitude of voltage is

e = 1.89 x 10^-7 V

induced current, i = e / R = (1.89 x 10^-7) / 3

i = 6.3 x 10^-8 A

8 0

3 years ago

Rubber is which of the following?

MariettaO [177]

Rubber is an insulator

8 0

3 years ago

Which of the following shows a balanced nuclear reaction?

miskamm [114]

Answer:

No. 2

Explanation:

6 0

3 years ago

Read 2 more answers

A double slit that is illuminated with coherent light of wavelength 644 nm produces a pattern of bright and dark fringes on a sc

shutvik [7]

Answer:

$2.77$ cm

Explanation:

$d$ = separation between the slits = 2783 x 10⁻⁹ m

$\lambda$ = wavelength of coherent light = 644 nm = 644 x 10⁻⁹ m

$D$ = Distance of the screen = 6 cm = 0.06 m

$y_{n}$ = Position of nth bright fringe

Position of nth bright fringe is given as

$y_{n} = \frac{nD\lambda }{d}$

for n = 2

$y_{2} = \frac{nD\lambda }{d}$

$y_{2} = \frac{(2)(0.06)(644\times10^{-9}))}{2783\times10^{-9}}$

$y_{2} = 0.0278$ m

for n = 4

$y_{4} = \frac{nD\lambda }{d}$

$y_{4} = \frac{(4)(0.06)(644\times10^{-9}))}{2783\times10^{-9}}$

$y_{4} = 0.0555$ m

Distance between 4th and 2nd bright fringes is given as

$w = y_{4} - y_{2} = 0.0555 - 0.0278 = 0.0277 m$

$w = 2.77$ cm

8 0

3 years ago