A soccer ball was kicked . it had the mass of .42 kg and accelerated at 25m/s . what was the force?

An iron wire has length 8.0m and a diameter 0.50mm. The sir has a resistance R.

Rudik [331]

The resistance of the second wire is 16 R.
where R is the resistance of the first wire.

R = ρ $\frac{l}{A}$
where l = length of the wire
A = area of the wire
A = $\pi r^{2}$ where, r = $\frac{diameter of wire}{2}$

Thus, on finding the ratio of resistance of the two wires, we get,

$\frac{R1}{R2} = \frac{l1A2}{l2A1}$

here, R1 = R
l1 = 8m
l2 = 2m
A1=π $0.25^{2}$
A1=π $0.50^{2}$

we get. R2 = 16R

7 0

4 years ago

The gravitational force between Pluto and Charon is 3.61 × 1018 N. Pluto has a mass of 1.3 × 1022 kg, which is only slightly gre

raketka [301]

Answer:

The distance between Pluto and Charon is $1.96 \times 10^7 m$ 

Explanation:

Force of gravitation between two objects $F_g= \frac{G(M_1 M_2 )}{r^2}$

Where $M_1 \ and \ M_2$ are the masses of the objects,r is the distance between the objects

G is the universal gravitational constant= $6.67 \times 10^-^1^1 m^3/kg s^2$

Here mass of pluto = $1.3 \times 10^2^2 kg$

mass of charon = $1.6 \times 10^2^1 kg$

Force of gravitation $F_g=3.61 \times 10^1^8 N$

$F_g= \frac {G(M_1 M_2 )}{r^2}$

$r^2= \frac {G(M_1 M_2 )}{F_g }$

$r= \sqrt \frac{(G(M_1 M_2 )}{F_g}$

$=\sqrt \frac {((6.674\times 10^-^1^1) \times 1.3 \times 10^2^2 \times 1.6\times 10^2^1)}{(3.61 \times 10^1^8 )}$

= $\sqrt \frac {(13.88*10^32)}{(3.61*10^18)}$

= $1.96 \times10^7 m$

4 0

4 years ago

Read 2 more answers

Which records should you consult before determining if an animal is safe to ship

lozanna [386]

Your pet must have current vaccinations that are required by the place (state, country, etc.) that it will be entering. Your pet would also need a health certificate that was done by a licensed veterinarian.

6 0

3 years ago

A piece of purple plastic is charged with 8.51 × 106 extra electrons compared to its neutral state. what is its net electric cha

VARVARA [1.3K]

Each electron provides a charge of -1.602 × 10^-19 coulombs.

If there are 8.51 × 10^-6 extra electrons:

1 electron ____________ -1.602 × 10^-19 coulombs

8.51 × 10^6 electrons___x = -1.602 × 10^-19*8.51 × 10^6/1=-1.32× 10^-12 coulombs

So the extra electrons provide a charge of 1.32× 10^-12 coulombs.

So the net charge is -1.32× 10^-12 coulombs (there are more electrons besides those extra electrons, but there are also protons, so they don’t affect the net charge – the other electrons just compensate the charge of the protons).

8 0

3 years ago

Describe the composition of humus and why it is an effective organic fertilizer

kenny6666 [7]

Answer:

soil additive

Explanation:

Soil Additive

The three main components of humus are fulvic acid, humic acid and humin. The spongy nature of humus helps it to trap and hold water, this particular property also helps to aerate the soil as humus expands and contracts with available water.

3 0

2 years ago