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ivanzaharov [21]
3 years ago
6

What is the wavelength of an FM radio

Physics
1 answer:
AleksandrR [38]3 years ago
4 0

V = 3.0 x 10⁸ m/s         (This is the same for all types of electromagnetic waves)

f = 88.6 MHz = 8.86 x 10⁷ Hz

λ = ?

V = fλ

λ = V/f = (3 x 10⁸)/(8.86 x 10⁷)

  =  3.4 m     [Ans]

Hope this helps!

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A car can be braked to a stop from the autobahn-like speed of 206 km/h in 190 m. Assuming the acceleration is constant, find its
Llana [10]

Answer:

  • a = - 8.617 \frac{m}{s^2}
  • a =  - 0.8798 \ g
  • Tb = 6.64 \ s
  • \frac{Tb}{Tr} = 16.6

Explanation:

<h3>a and b</h3>

We can use the following formula, from kinematics:

(v_f)^2-(v_i)^2 = 2  \ a \  d

where v_f is the final speed, v_i is the initial speed, a is the acceleration and d the distance traveled.

Knowing that the final speed is zero, and the initial speed is

v_i = 206 \frac{km}{h} = 206 \frac{km}{h} \frac{1000 \ m}{1 \ km} \frac{1 \ h}{3600 \ s} = 57.22 \frac{m}{s}

we obtain

(0)^2-(57.22 \frac{m}{s})^2 = 2  \ a \  190 \ m

a = \frac{ - \ 3,274.13 \frac{m^2}{s^2} }{ 2 \ 190 \ m}

a = - 8.617 \frac{m}{s^2}

Now, knowing that

g = 9.806 \frac{m}{s^2}

then

a = \frac{- 8.617 \frac{m}{s^2}} { 9.806 \frac{m}{s^2} } \ g

a = -  0.8798 \ g

<h3>c</h3>

We can use the following formula

v(t) = v_0 + a t

so

0 =  57.22 \frac{m}{s} - 8.617 \frac{m}{s^2} \ Tb

Tb = \frac{ 57.22 \frac{m}{s} }{ 8.617 \frac{m}{s^2} }

Tb = 6.64 \ s

<h3>d</h3>

\frac{Tb}{Tr} = \frac{ 6.64 \ s }{ 0.4 s }

\frac{Tb}{Tr} = 16.6

3 0
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7 0
3 years ago
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NeX [460]
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What is the major difference between the natural frequency and the damped frequency of oscillation.​
natita [175]

Answer:

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<u>Answer:</u>

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