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3 years ago

What is the wavelength of an FM radio

Physics

1 answer:

AleksandrR [38]3 years ago

4 0

V = 3.0 x 10⁸ m/s (This is the same for all types of electromagnetic waves)

f = 88.6 MHz = 8.86 x 10⁷ Hz

λ = ?

V = fλ

λ = V/f = (3 x 10⁸)/(8.86 x 10⁷)

= 3.4 m [Ans]

Hope this helps!

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A car can be braked to a stop from the autobahn-like speed of 206 km/h in 190 m. Assuming the acceleration is constant, find its

Llana [10]

Answer:

$a = - 8.617 \frac{m}{s^2}$

$a = - 0.8798 \ g$

$Tb = 6.64 \ s$

$\frac{Tb}{Tr} = 16.6$

Explanation:

We can use the following formula, from kinematics:

$(v_f)^2-(v_i)^2 = 2 \ a \ d$

where $v_f$ is the final speed, $v_i$ is the initial speed, a is the acceleration and d the distance traveled.

Knowing that the final speed is zero, and the initial speed is

$v_i = 206 \frac{km}{h} = 206 \frac{km}{h} \frac{1000 \ m}{1 \ km} \frac{1 \ h}{3600 \ s} = 57.22 \frac{m}{s}$

we obtain

$(0)^2-(57.22 \frac{m}{s})^2 = 2 \ a \ 190 \ m$

$a = \frac{ - \ 3,274.13 \frac{m^2}{s^2} }{ 2 \ 190 \ m}$

$a = - 8.617 \frac{m}{s^2}$

Now, knowing that

$g = 9.806 \frac{m}{s^2}$

then

$a = \frac{- 8.617 \frac{m}{s^2}} { 9.806 \frac{m}{s^2} } \ g$

$a = - 0.8798 \ g$

We can use the following formula

$v(t) = v_0 + a t$

$0 = 57.22 \frac{m}{s} - 8.617 \frac{m}{s^2} \ Tb$

$Tb = \frac{ 57.22 \frac{m}{s} }{ 8.617 \frac{m}{s^2} }$

$Tb = 6.64 \ s$

$\frac{Tb}{Tr} = \frac{ 6.64 \ s }{ 0.4 s }$

$\frac{Tb}{Tr} = 16.6$

3 0

3 years ago

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adoni [48]

The correct matches are as follows:

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<span>
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7 0

3 years ago

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NeX [460]

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5 0

3 years ago

What is the major difference between the natural frequency and the damped frequency of oscillation.

natita [175]

Answer:

This causes the amplitude of the oscillation to decay over time. The damped oscillation frequency does not equal the natural frequency. Damping causes the frequency of the damped oscillation to be slightly less than the natural frequency

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2 years ago

Find the pressure exerted on the floor by a 100N box whose bottom area is 40cm x<br> 50cm.

Mazyrski [523]

<u>Answer:</u>

Pressure exerted = 500 Pa

<u>Explanation:</u>

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