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guajiro [1.7K]
3 years ago
6

Which equation represents the total energy of a system

Physics
1 answer:
Troyanec [42]3 years ago
6 0
The conservation of energy equation?
K1 + U1 = K2 + U2

Or the Kinetic energy equation?
KE = 1/2 mv²

Gravitational potential energy?
Ug = mgΔy

Elastic potential energy?
Ue = 1/2 kx²
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Explanation:

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g= acceleration due to gravity

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When dots are printed from a laser printer to form letters, they must be close enough so that you do not see the individual dots
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I don't understand this QUESTION​
alex41 [277]

This electric force calculator will enable you to determine the repulsive or attractive force between two static charged particles. Continue reading to get a better understanding of Coulomb's law, the conditions of its validity, and the physical interpretation of the obtained result.

How to use Coulomb's law

Coulomb's law, otherwise known as Coulomb's inverse-square law, describes the electrostatic force acting between two charges. The force acts along the shortest line that joins the charges. It is repulsive if both charges have the same sign and attractive if they have opposite signs.

Coulomb's law is formulated as follows:

F = keq₁q₂/r²

where:

F is the electrostatic force between charges (in Newtons),

q₁ is the magnitude of the first charge (in Coulombs),

q₂ is the magnitude of the second charge (in Coulombs),

r is the shortest distance between the charges (in m),

ke is the Coulomb's constant. It is equal to 8.98755 × 10⁹ N·m²/C². This value is already embedded in the calculator - you don't have to remember it :)

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A student is concerned about background radiation that she is exposed to. She claims that nuclear power plants have caused backg
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3 years ago
Read 2 more answers
A spring with k = 19.5 N/cm is initially stretched 1.39 cm from its equilibrium length. a) How much more energy is needed to fur
lara31 [8.8K]

Answer:

Energy needed = 54.02 J

Explanation:

the Energy in an elastic spring from hookes law is given  as

F= ke , therefore the energy (E) is

E = \frac{1}{2} Ke^{2}

K = 19.5 N/cm

e = 1.39cm

E = \frac{1}{2} x 19.5 x 1.39

E = 13.55 J

The energy to stretch the spring for 6.93cm is

E = \frac{1}{2} x 19.5 x 6.93

E = 67.57 J

The more energy needed for the further stretch is

67.57 - 13.55

Energy needed = 54.02 J

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