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AveGali [126]
3 years ago
13

If a wave has a wavelength of 2m and a frequency of 500 hz, what is its speed

Physics
1 answer:
Archy [21]3 years ago
8 0

Answer:

1000

Explanation:

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sleet_krkn [62]

Answer:

e

Explanation:

4 0
2 years ago
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All of the planets stay near the ecliptic as they move on the Celestial Sphere
stellarik [79]

Answer:

True

Explanation:

As the Earth goes around the Sun, it will appear that Earth is stationary and Sun is going around it. One can observe the same in real life as well. This apparent path followed by the Sun is called Ecliptic. The plane consisting Ecliptic is called as Ecliptic plane which is same as the orbital plane of Earth.

All the planets of the Solar system are also going around the Sun. Their orbital plane has negligible tilt with respect to Ecliptic plane. Due to this the planets will always appear near to the Ecliptic as they move on the celestial sphere.

3 0
3 years ago
Which of the following lists contains only examples of renewable sources of energy?
anyanavicka [17]
<h3><u>Answer;</u></h3>

A. wind, tidal, geothermal, and hydroelectric

<h3><u>Explanation</u>;</h3>
  • Renewable energy sources are the energy sources that are constantly being replenished, such as sunlight, wind, and water. This means that we can use them as much as we want, and we do not have to worry about them running out.
  • Additionally, renewable energy sources are usually much more environmentally friendly than fossil fuels. Examples of renewable sources of energy includes; solar energy, wind energy, hydroelectric power, tidal energy, geothermal energy, etc.
5 0
3 years ago
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Answer this question, please​
pashok25 [27]

Answer:

the correct answer is the 60

+ 20 + 60 \gamma  \beta

3 0
3 years ago
24 A uniform electric field of magnitude 1.1×104 N/C is perpendicular to a square sheet with sides 2.0 m long. What is the elect
Tatiana [17]

Answer:

44,000 Nm^2/C

Explanation:

The electric flux through a certain surface is given by (for a uniform field):

\Phi = EA cos \theta

where:

E is the magnitude of the electric field

A is the area of the surface

\theta is the angle between the direction of the field and of the normal to the surface

In this problem, we have:

E=1.1\cdot 10^4 N/C is the electric field

L = 2.0 m is the side of the sheet, so the area is

A=L^2=(2.0)^2=4.0 m^2

\theta=0^{\circ}, since the electric field is perpendicular to the surface

Therefore, the electric flux is

\Phi =(1.1\cdot 10^4)(4.0)(cos 0^{\circ})=44,000 Nm^2/C

4 0
2 years ago
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