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jeka94
3 years ago
13

I am child in the family

Mathematics
2 answers:
Orlov [11]3 years ago
7 0

Answer:

So,you r saying that you r the only 1 child in your family....

uranmaximum [27]3 years ago
5 0

Answer:

why this question ?!

giving points?!

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Why does dividing by 100 shift each digit two places to the right?
alekssr [168]
The answer is D. If you divide 1000 by 100, it is 10. 10 is equal to 1/100 of its previous value of 1000.
3 0
3 years ago
A walkway forms one diagonal of a square playground. The walkway is 14 m long. How long is a side of the playground?
Vilka [71]

Answer: The side of the playground is around 10 meters long

Step-by-step explanation:

use the diagonal as the hypotenuse of a right triangle, where the sides of the square form the legs of said triangle.

Usually

a^{2} +b^{2} =c^{2}

since we know a and b are the same length (sides of a square are congruent) we would have

a^{2} +a^{2} =c^{2} \\2a^{2} =c^{2}

We know that c is 14 so

2a^{2} =14^{2} \\2a^{2} =196\\a^{2} =98\\a=\sqrt{98} \\a= 9.999

5 0
2 years ago
A textile manufacturer wants to set up a control chart for irregularities (eg. oil stains, shop soil, loose threads, and tears)
Nookie1986 [14]

Answer:

UCLc = 25.7715519

LCLc =-4.171551971

find attached the C-chart(control chart)

Step-by-step explanation:

Sample Irregularities Sample Irregularity Sample Irregularity

1 18 6 11 11 10

2 14 7 4 12 16

3 6 8 10 13 5

4 14 9 12 14 15

5 8 10 9 15 17

Samples/Irre Cont'd

16 - 4

17 - 15

18 - 9

19 - 15

20 - 17

Using these? data, set up a? c-chart with z =33.

UCLc =

LCLc =

     Sample irreg     mean(CL) UCL LCL

              ularities

1 18 10.8 25.77155197 -4.171551971

2 14 10.8 25.77155197 -4.171551971

3 6 10.8 25.77155197 -4.171551971

4 14 10.8 25.77155197 -4.171551971

5 8 10.8 25.77155197 -4.171551971

6 11 10.8 25.77155197 -4.171551971

7 4 10.8 25.77155197 -4.171551971

8 10 10.8 25.77155197 -4.171551971

9 12 10.8 25.77155197 -4.171551971

10 9 10.8 25.77155197 -4.171551971

11 11 10.8 25.77155197 -4.171551971

12 16 10.8 25.77155197 -4.171551971

13 5 10.8 25.77155197 -4.171551971

14 1 10.8 25.77155197 -4.171551971

15 17 10.8 25.77155197 -4.171551971

16 4 10.8 25.77155197 -4.171551971

17 15 10.8 25.77155197 -4.171551971

18 9 10.8 25.77155197 -4.171551971

19 15 10.8 25.77155197 -4.171551971

20 17 10.8 25.77155197 -4.171551971

find attached the C-chart

Download xlsx
5 0
3 years ago
The equation 4x + 3 = 4x + 3 has infinite solutions.<br> giving brainiest
Oksanka [162]

Answer:

yes that is correct. Do you have a question about it?

7 0
2 years ago
Read 2 more answers
Anyone can help me solve this equation using cross multiplying
Natali5045456 [20]

9514 1404 393

Answer:

  x = 1 or 5

Step-by-step explanation:

The notion of "cross-multiplying" is the idea that the numerator on the left is multiplied by the denominator on the right, and the numerator on the right is multiplied by the denominator on the left. This looks like ...

  \displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\ \longrightarrow\ (x-1)(3x-1)=(7)(2x-2)

Then the solution proceeds by eliminating parentheses, and solving the resulting quadratic equation.

  3x^2-4x+1=14x-14\\\\3x^2-18x+15=0\qquad\text{subtract $14x-14$}\\\\x^2-6x+5=0 \qquad\text{divide by 3}\\\\(x-1)(x-5)=0\qquad\text{factor}\\\\x\in\{1,5\}

_____

<em>Comment on "cross multiply"</em>

Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes <em>what the result looks like</em>. It doesn't adequately describe how you get there. The <em>one and only rule</em> in solving Algebra problems is "<em>whatever is done to one side of the equation must also be done to the other side of the equation</em>." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.

What looks like "cross multiply" is really "<em>multiply by the product of the denominators</em> and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.

  \displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\\\\\frac{x-1}{7}\times7(3x-1)=\frac{2x-2}{3x-1}\times7(3x-1)\\\\(x-1)(3x-1)=(2x-2)(7)\qquad\textit{looks like}\text{ cross multiply}

8 0
2 years ago
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