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ELEN [110]
3 years ago
14

Which scientist is credited with first stating that electrons orbit an atomic nucleus

Chemistry
1 answer:
LenaWriter [7]3 years ago
8 0
The scientist which was credited with first stating that electrons orbit an atomic nucleus was Niels Henrik David Bohr. He was the proponent of the Bohr model of the atom, wherein he states that energy level of electrons are distinct and that electrons revolve on stable orbits within the atomic nucleus but can actually transfer from one orbit (level) to another. The orbitals are called: s, p, d and f orbitals.
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Answer:

yes

Explanation:

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Name this compound Cr2(CO3)3
kiruha [24]

Answer:

Molecular Weight

Explanation:

Chromium(III) Carbonate Cr2(CO3)3 Molecular Weight -- EndMemo.

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Cuales son los compuestos químicos inorgánicos utilizados en la formación de huesos
Ilia_Sergeevich [38]

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Explanation:

?

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3 years ago
A balloon containing helium gas expands from 230
Anit [1.1K]

The answer for the following problem is mentioned below.

  • <u><em>Therefore the final  moles of the gas is 14.2 × </em></u>10^{-4}<u><em> moles.</em></u>

Explanation:

Given:

Initial volume (V_{1}) = 230 ml

Final volume (V_{2}) = 860 ml

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Final moles (n_{2})

We know;

According to the ideal gas equation;

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where;

P represents the pressure of the gas

V represents the volume of the gas

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T represents the temperature of the gas

So;

    V ∝ n

\frac{V_{1} }{V_{2} } = \frac{n_{1} }{n_{2} }

where,

(V_{1}) represents the initial volume of the gas

(V_{2}) represents the final volume of the gas

(n_{1}) represents the initial  moles of the gas

(n_{2}) represents the final moles of the gas

Substituting the above values;

   \frac{230}{860} = \frac{3.8 * 10^-4}{n_{2} }

  n_{2} = 14.2 × 10^{-4} moles

<u><em>Therefore the final  moles of the gas is 14.2 × </em></u>10^{-4}<u><em> moles.</em></u>

7 0
3 years ago
What happens when balloon filled with CO2 is released in air​
statuscvo [17]
I don’t actually know for sure, but I think it would sink. Most of the mass of the molecule is from the oxygen.
Amu of O2 = 32
Amu of C = 12
And since most of the balloon is oxygen, it has no reason to actually float. It would be denser than the air, I’d imagine. I could be totally wrong here, I’m guessing based on my knowledge of chemistry
5 0
3 years ago
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