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allsm [11]
3 years ago
13

The main difference between speed and velocity is that velocity includes this:

Chemistry
1 answer:
Leokris [45]3 years ago
3 0
<h3>Answer:</h3>

Direction

<h3>Explanation:</h3>

The question is testing on vector and scalar quantities.

What are vector quantities and scalar quantities?

  • Quantities with both magnitude and direction are known as vector quantities while those with only magnitude are known as scalar quantities.

What are the examples of vector and scalar Quantities?

  • Vector quantities examples- Velocity, force, displacement, etc
  • Scalar quantities examples - Speed, distance, temperature, mass, etc

What would be the difference of speed and velocity then?

  • Speed and velocity differ in that velocity has both magnitude and direction (vector quantity) while speed has magnitude only (scalar quantity).

Further Explanation;

  • Velocity refers to the  rate of change in displacement of a body in motion
  • It is given by, Velocity = Displacement ÷ time
  • Speed on the other hand is the rate of change in distance of body.
  • It is calculated by, Speed = Distance ÷ time
  • Displacement is the distance in a specified direction.
  • Velocity and displacement are vector quantity in that they have both magnitude and direction.
  • Speed and distance on the other hand lack direction and thus are scalar quantity since they only have magnitude.
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Classify methanal according to the position of the c=o group
seraphim [82]

Answer :  Methanal also known as Formaldehyde CH_{2}O is a chemical Aldehyde which contain ( -CHO) group.

Explanation :

In organic chemistry, a carbonyl group is a functional group which contain a carbon atom double-bonded to an oxygen atom i.e, ( C=O).

     If carbonyl group is present in a compound then it can be a carboxylic (RCOOH), aldehyde (RCHO), ketone (RCOR'), ester ((RCOOR') or amide (RCONR'R") group.

Here are some functional groups naming according to the<em> IUPAC</em> rules and image also attached,

Carboxylic acid   →    (RCOOH)    →    ( name end in 'OIC ACID' )

Aldehyde             →    (RCOH)       →    ( name end in 'AL' )

Ketone                 →    (RCOR')       →    ( name end in 'ONE' )

Ester                     →    (RCOOR')    →    ( name end in 'ATE' )

Amide                   →    (RCONR'R") →    ( name end in 'AMIDE' )

In an aldehyde, atleast one hydrogen atom must be attached to the carbonyl carbon. For an aldehyde, remove ( -e) from alkane name and add ( -al) at the end of the compound.

Methanal is the IUPAC name for Formaldehyde.


3 0
3 years ago
Need helpppp please
Vladimir79 [104]

Answer:

message me so i can help you because i cant see the words

Explanation:

6 0
2 years ago
One of these notations represents the definition of one mole. That is
just olya [345]

Answer:

6.02*10^23

Explanation:

This is the number for one mole. Just like one dozen = 12, one mole = 6.02*10^23.

Fun fact, if you had a mole of pennies you could spend 1 million dollars every second of your life and not have even spent 1% of it by the time you die at 100 years old.

3 0
3 years ago
Lead(II) nitrate is added slowly to a solution that is 0.0800 M in Cl− ions. Calculate the concentration of Pb2+ ions (in mol /
barxatty [35]

Answer:

[Pb^{2+}]=3.9 \times 10^{-2}M

this is the concentration required to initiate precipitation

Explanation:

PbCl_2  ⇄ Pb^{2+}+2Cl^-

Precipitation starts when ionic product is greater than solubility product.

Ip>Ksp

Precipitation starts only when solution is supersaturated because solution become supersaturated then it does not stay in this form and precipitation starts itself only solution become saturated.

This usually happens when two solutions containing separate sources of cation and anion are mixed together and here also we are mixing lead (||)nitrate solution(source of lead(||)) into the Cl- solution.

Ip=[Pb^{2}][2Cl^-]^2=Ksp

Ksp=2.4\times 10^{-4}

lets solubility=S

[Pb^{2+}] = S

[Cl^-]=2S

Ksp=[Pb^{2+}]\times [Cl^-]^2

Ksp=S \times (2S)^2

Ksp=4S^3

S=\sqrt[3]{\frac{Ksp}{4} }

S=3.9\times 10^{-2}

[Pb^{2+}]=3.9 \times 10^{-2}M this is the concentration required to initiate precipitation

4 0
3 years ago
CaC2 + 2H2O → C2H2 + Ca(OH)2 If 2.8 moles of CaC2 are consumed in this reaction, how many grams of H2O are needed?
Strike441 [17]

Answer:

Cac2 is a answer please mark me brainliest

8 0
2 years ago
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