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Schach [20]
3 years ago
12

Helpppppppppppppppppppppppp

Chemistry
1 answer:
Greeley [361]3 years ago
3 0
B, the height above or below sea level
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A chemist has 3.55x1022 molecules of nitrogen monoxide. How
Alina [70]

Answer:

<h2>0.059 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{3.55 \times  {10}^{22} }{6.02 \times  {10}^{23} }  \\  = 0.05897...

We have the final answer as

<h3>0.059 moles</h3>

Hope this helps you

6 0
3 years ago
During a reaction 24 cubic cm of carbon dioxide was given off. After 8 minutes no more gas was produced and the reaction was com
yuradex [85]

Answer:

Explanation:

Given parameters:

Volume of CO₂ = 24cm³

time taken for the reaction to complete = 8minutes.

Unknown:

rate of reaction

Soution

The reaction rate is a measure of speed of a chemical reaction. It is often calculated using the expression below:

    Reaction rate = \frac{change in concentration of reactant/product}{time taken}

   Reaction rate = \frac{24}{8} = 3cm³/min

In this reaction, 3cm³ of carbon dioxide were produced per minute

7 0
2 years ago
Read 2 more answers
The action of the weather conditions in altering the color, texture, composition, or form of exposed is called ___________. (A)
balu736 [363]

Answer:

Explanation:

YES BECAUSE YE SIS YES WHEN YES=\sqrt{x} x^{2} x^{2} \neq \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]

GAMER MOMENT FROM LUIGI FOR⇔\sqrt{x} x^{2} x^{2} \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \alpha \alpha \alpha x_{123} \frac{x}{y} \pi \neq \geq \leq \\ \left \{ {{y=2} \atop {x=2}} \right. \int\limits^a_b {x} \, dx x^{2} \sqrt{x} \sqrt{x} \\

3 0
2 years ago
Algae and other phytoplankton are the major producers of the earth's:
vredina [299]

Answer:

oxygen

Explanation:

pls mark me brainliest right

4 0
2 years ago
A 13.97 g sample of nabr contains 22.34% na by mass. Considering the law of constant composition (definite proportions) how many
Grace [21]

As per the law of constant composition, a given sample will always contain the same number of elements that combine in the same mass proportion.

Therefore if a sample of 13.97 g of NaBr contains 22.39 % of Na by mass then,  a sample of 5.75 g of NaBr would also contain 22.39% Na by mass

Hence:

Mass of Na = 5.75 g * 22.39/100 = 1.287 g

5.75 g of NaBr would contain 1.29 g of Na

3 0
3 years ago
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