Answer:
To=20.44 °C
Explanation:
Given that
Velocity , v= 30 m/s
Temperature , T= 20°C
We know that specific heat capacity for air ,Cp=1.005 kJ/kg.K
By using energy conservation ,the stagnation temperature is given as
Now by putting the values in the above equation we get
To= 293.44 K
To= 293.44 - 273 °C
To=20.44 °C
Therefore the stagnation temperature will be 20.44 °C.
Explanation:
An object's acceleration is the rate its velocity (speed and direction) changes. Therefore, an object can accelerate even if its speed is constant - if its direction changes. ... Light's acceleration is zero. Since it travels in a straight line, its direction does not change.
Answer:
Gravity: downwards
Air drag and air-pressure on the inner surface of the the parachute: Upwards
Explanation:
- If a sky-diver is in the final stages of his descend with open parachute such that the wind is calm and it does not blows him laterally.
- In such a condition the air resistance in the form of drag and the pressure force due to the air captured in the parachute are acting in the upward direction which balance the force of gravity on the body. But this situation may occur momentarily and then again the diver must begin to slowly descend.
Answer:
10 m/s
Explanation:
The problem can be solved by using the law of conservation of momentum: the initial momentum has to be equal to the final momentum, so we can write the following
where
is the mass of the first car
is the initial velocity of the first car
is the mass of the second car
is the initial velocity of the second car
is the final velocity of the two combined cars after the collision
Re-arranging the equation and substituting the numbers, we find
Based on the scenario,
The thing that the result say about distance covered is :
it tells you that the distance covered is equal to the average speed times the travel time
hope this helps
