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CaHeK987 [17]
4 years ago
15

Unpolarized light passes through two polarizers. Find the fraction of light from the first polarizer that gets through the secon

d when the angle between their transmission axes is 60 degree.
Physics
2 answers:
meriva4 years ago
8 0

Answer:

0.5

Explanation:

Data provided in the question:

The angle between their transmission axes, θ = 60°

Now,

We have the relation,

I₁ = I₀cos²θ

where,

I₁ is the intensity of the transmitted light

I₀ is the intensity of the incident light

on rearranging, we get

\frac{I_1}{I_0}=cos²60°

or

\frac{I_1}{I_0}=0.5

klasskru [66]4 years ago
7 0

Answer:

1/4

Explanation:

Let I₀ be the intensity of polarised light from first polariser . After first polarisation, in the second polarisation, intensity changes as follows

I = I₀  Cos² θ⁰

I = I₀  Cos² 60⁰

=  I₀  1 / 2² = I₀ / 4

So , 1/4 or one fourth of intensity from first polariser gets through the second polariser.

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guajiro [1.7K]
In the given question all the required details are given. Using these information's a person can easily find the momentum of the object. In the question it is already given that the mass of the object is 5 kg and the velocity at which it is traveling is 1.2 m/s.
We know the equation of finding momentum as
Momentum = mass * velocity
                   = 5 * 1.2
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PLEASE ANSWER FIRST GETS BRAINLIEST
Oksanka [162]

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7 0
3 years ago
The absolute pressure in water at a depth of 5m is read to be 145 kPa. Determine (a) the local atmospheric pressure, and (b) the
irga5000 [103]

Answer:

a) 95950 pascals

b) 137642.5 pascals

Explanation:

The absolute pressure (Pabs) on a fluid is:

P_{abs}=P_{gauge}+P_{atm} (1)

With Pgauge the pressure due depth on the fluid and Patm the atmospheric pressure. Pgauge is equal to:

P_{gauge}=\rho gh (2)

with ρ the fluid density, g the gravitational acceleration and h the depth on the fluid. Using (2) on (1) and solving for Patm:

P_{atm}=P_{abs}-P_{gauge}=P_{abs}-\rho_{water} gh

P_{atm}=(145000Pa)-(1000\frac{kg}{m^{3}})(9.81\frac{m}{s^{2}})(5m)

P_{atm}=95950Pa

b) Here we're going to use again (1) but now we have another value of density because it's other liquid, to know that value we should use the fact that specific gravity (S.G) for liquids is the ratio between fluid density and water density:

S.G=\frac{\rho_{fluid}}{\rho_{water}}

\rho_{liquid}=S.G*\rho_{water}

\rho_{liquid}=(0.85)*(1000\frac{kg}{m^{3}})=850\frac{kg}{m^{3}}

so:

P_{abs}=\rho_{liquid} gh+P_{atm}=(850\frac{kg}{m^{3}})(9.81\frac{m}{s})(5m)+95950Pa

P_{abs}=137642.5 Pa

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3 years ago
WILL BE BRAINLIEST <br> HELP!!!
ivolga24 [154]

Answer:

(8.0÷6.0)×10[(-2)-(-3)]

6 0
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