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CaHeK987 [17]
4 years ago
15

Unpolarized light passes through two polarizers. Find the fraction of light from the first polarizer that gets through the secon

d when the angle between their transmission axes is 60 degree.
Physics
2 answers:
meriva4 years ago
8 0

Answer:

0.5

Explanation:

Data provided in the question:

The angle between their transmission axes, θ = 60°

Now,

We have the relation,

I₁ = I₀cos²θ

where,

I₁ is the intensity of the transmitted light

I₀ is the intensity of the incident light

on rearranging, we get

\frac{I_1}{I_0}=cos²60°

or

\frac{I_1}{I_0}=0.5

klasskru [66]4 years ago
7 0

Answer:

1/4

Explanation:

Let I₀ be the intensity of polarised light from first polariser . After first polarisation, in the second polarisation, intensity changes as follows

I = I₀  Cos² θ⁰

I = I₀  Cos² 60⁰

=  I₀  1 / 2² = I₀ / 4

So , 1/4 or one fourth of intensity from first polariser gets through the second polariser.

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What would happen to a moving object if no unbalanced force acts upon it?<br> Help please?
Kisachek [45]

Answer:

B

Explanation:

if no force acts upon it it will just continue moving

hope this helps!! have a wonderfull day!

7 0
3 years ago
In 1932 Albert Dremel of Racine, Wisconsin, created his rotary tool that has come to be known as a dremel.
kramer

Answer:

3054.32618 rad/s²

-431.1989 rad/s²

29080

Explanation:

Converting angular speed to rad/s

\omega=35000\times \frac{2\pi}{60}=3665.19142\ rad/s

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{3665.19142-0}{1.2}\\\Rightarrow a=3054.32618\ rad/s^2

The average acceleration while speeding up is 3054.32618 rad/s²

The number of turns in the 1.2 seconds

\theta=\omega_it+\frac{1}{2}\alpha t^2\\\Rightarrow \theta=0\times t+\frac{1}{2}\times 3054.32618\times 1.2^2\\\Rightarrow \theta=2199.11484\ rad=\frac{2199.11484}{2\pi}=349.99\ rotations

The number of rotations in the 1.2 seconds is 349.99

Number of rotations in the 45 seconds

\frac{35000}{60}\times 45=26250\ rotations

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{0-3665.19142}{8.5}\\\Rightarrow a=-431.1989\ rad/s^2

Average angular acceleration while slowing down -431.1989 rad/s²

\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \theta=\frac{\omega_f^2-\omega_i^2^2}{2\alpha}\\\Rightarrow \theta=\frac{0^2-3665.19142^2}{2\times -431.1989}\\\Rightarrow \theta=15577.0668\ rad=\frac{15577.0668}{2\pi}\\ =2479.16718\ rotations

Number of rotations while slowing down is 2479.16718

Total number of rotations is 349.99+26250+2479.16718 = 29079.15718 = 29080

3 0
3 years ago
A 73-kg person in a moving car stops during a car collision in a distance of 0.80 m . The stopping force that the air bag exerts
fredd [130]

Answer:

 v₀ = 13.24 m / s

Explanation:

Let's use Newton's second law to find the average acceleration during the crash

       F = m a

.       a = F / m

       a = 8000/73

       a = 109.59 m / s²

Now we can use the kinematic equations to find the initial velocity, since when the velocity stops it is zero (v = 0)

       v² = v₀² - 2 a x

       v₀² = 2 a x

       v₀ = √  2 a x

       v₀ = √ (2 109.59 0.80)

       v₀ = 13.24 m / s

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# of protons found in the nucleus of an atom of that element,and, therefore identical to the charged nucleus.
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