Hello!
Let's begin by doing a summation of torques, placing the pivot point at the attachment point of the rod to the wall.

We have two torques acting on the rod:
- Force of gravity at the center of mass (d = 0.700 m)
- VERTICAL component of the tension at a distance of 'L' (L = 2.200 m)
Both of these act in opposite directions. Let's use the equation for torque:

Doing the summation using their respective lever arms:


Our unknown is 'theta' - the angle the string forms with the rod. Let's use right triangle trig to solve:

Now, let's solve for 'T'.

Plugging in the values:

Answer:
Explanation:
A.
Given:
Vo = 21 m/s
Vf = 0 m/s
Using equation of Motion,
Vf^2 = Vo^2 - 2aS
S = (21^2)/2 × 9.8
= 22.5 m.
B.
Given:
S = 22.5 + 21 mm
= 22.521 m
Vo = 0 m/s
Using the equation of motion,
S = Vo × t + 1/2 × a × t^2
22.521 = 0 + 1/2 × 9.8 × t^2
t^2 = (2 × 22.521)/9.8
= 4.6
t = 2.14 s
The final speed of a lion running 30 m/s accelerates at a rate of 3 m/s3 for 5 seconds it’s 3.2