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emmasim [6.3K]
2 years ago
14

Which of the following is a type of T cell?

Physics
2 answers:
Bess [88]2 years ago
7 0

Answer:

D

Explanation:

DanielleElmas [232]2 years ago
7 0

Answer:

its D

Explanation:

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During an experiment, a toy car accelerates forward for a total time of 5 s. Which of the following procedures could a student u
levacccp [35]

Answer: B

Explanation: The motion sensor will measure the speed (velocity) of the car. Since the mass of the car has been measured, we can use formulas to calculate the average force.

Average net force = mass × acceleration

The mass of the toy car is measured first and noted

To calculate the velocity,

the car starts from rest since the velocity is associated with the distance and time after 5s.

Acceleration = velocity/time

With that the acceleration can be found.

acceleration is defined as change in velocity per unit time.

Then,

Force = mass × acceleration

Option B is the best answer

3 0
3 years ago
If it takes 150N of force to move a box 10 meters. what is the work done on the box?
sergeinik [125]

Answer:

1500 Joules

Explanation:

Work = Force x Distance

When multiplying by 10 you simply shift all the digits to the

left and append a 0 to the end.

so 150 x 10 = 1500 Joules

3 0
2 years ago
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List two pieces of evidence<br> related to this picture
tatyana61 [14]

Answer:

there was a crash you can tell cause of the 2 cars the dog is curious on what happened, you can tell because the dog is looking at the cash

4 0
3 years ago
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An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.50 mm. A 25
torisob [31]

Answer:

The electric field is 16666.66 V/m.

The surface charge density is 1.474\times10^{-7}\ C/m^2

The capacitance is 4.484\times10^{-12}\ F

The charge on each plate is 112.1\times10^{-12}\ C

Explanation:

Given that,

Area =7.70 cm²

Distance = 1.50 mm

Potential difference = 25.0 V

Suppose  we find the electric field between the plates, the surface charge density, the capacitance and the charge on each plates.

We need to calculate the electric field

Using formula of electric field

E=\dfrac{V}{d}

Put the value into the formula

E=\dfrac{25.0}{1.50\times10^{-3}}

E=16666.66\ V/m

We need to calculate the charge density

Using formula of charge density

\sigma=E\times\epsilon_{0}

Put the value into the formula

\sigma=16666.66\times8.85\times10^{-12}

\sigma=1.474\times10^{-7}\ C/m^2

We need to calculate the capacitance

Using formula of capacitance

C=\dfrac{\epsilon_{0}A}{d}

Put the value into the formula

C=\dfrac{8.85\times10^{-12}\times7.60\times10^{-4}}{1.50\times10^{-3}}

C=4.484\times10^{-12}\ F

We need to calculate the charge

Using formula of charge

q=CV

Put the value into the formula

q=4.484\times10^{-12}\times25.0

q=112.1\times10^{-12}\ C

Hence, The electric field is 16666.66 V/m.

The surface charge density is 1.474\times10^{-7}\ C/m^2

The capacitance is 4.484\times10^{-12}\ F

The charge on each plate is 112.1\times10^{-12}\ C

8 0
3 years ago
The hardest known natural material is _____. <br> jade<br> quartz<br> diamond<br> talc
kakasveta [241]
Its diamond i am 100% right!

8 0
3 years ago
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