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4 years ago

10

a truck drives up a hill with a 15 incline. if the truck has a constant speed of 22m/s, what are the horizontal and vertical com

ponents of the trucks velocity

1 answer:

Kamila [148]4 years ago

3 0

Answer:

speed of truck (v) = 22 m/s ,

angle of hill (Θ) =15°

Find

Vertical component (Fv) = ?

Harizontal component (Fh) =?

Vertical component (Fh) = V cosΘ

= 22. cos 15

= 21.25 m/s.

Harizontal component (Fv) = V sinΘ

= 22. sin 15

= 5.69 m/s.

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Which of the following is the most usable form of nitrogen to plants?

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Ammonia because it doesn't have nitrogen

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3 years ago

Explain ALL THREE of Newton’s Laws in your own words.

Svet_ta [14]

Explanation:

(1) Every object moves in a straight line unless acted upon by a force. (2) The acceleration of an object is directly proportional to the net force exerted and inversely proportional to the object's mass. (3) For every action, there is an equal and opposite reaction.

5 0

3 years ago

I need an answer fast plz

Zina [86]

Answer:

L = 1.5 [m]

Explanation:

To find the Force Z we must perform a sum of forces on the Y-axis equal to zero, (it is equal to zero since there is no movement, the beam is in equilibrium).

ΣFy = 0

- 30 - 20 - 40 + Z = 0

Z = 90 [N]

Now to find the length of the beam, we must perform a sum of moments equal to zero at the midpoint of the beam, where the load Z is applied.it is important to clarify that the moment generated by the force of 30[N] tends to rotate the beam counterclockwise (is taken as positive), while the load of 20 [N], tends to rotate the beam Clockwise (is taken as negative).

ΣM = 0

+ (30*0.5) - (20*x) = 0

15 = 20*x

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8 0

3 years ago

A particle P with speed 140 m s–1begins to decelerate uniformly at a certain instant while another particle Q starts from rest 6

Natasha2012 [34]

Answer:

i) The motion of both particles are shown on the same speed-time curve included

ii) Approximately 19.5 seconds

Explanation:

We are given that;

Initial velocity of particle, P = 140 m/s

Start time of particle P = 6 s before start time of particle Q

Position of particle Q when velocity is 25 m/s = 125 m

Therefore, from the equation of motion, we have for particle Q;

v² = u² + 2·a·s

Where:

v = Final velocity = 25 m/s

u = Initial velocity = 0 m/s

a = Acceleration

s = Distance covered = 125 m

Therefore;

25² = 0² + 2×a×125

Which gives a = 25²/(2×125) = 2.5 m/s²

The time taken for particle Q to reach 125 m is found from the relation;

s = u·t + 1/2·a·t²

Where:

t = Time of journey

Therefore;

125 = 0×t + 1/2×2.5×t²

Which gives 125 = 1.25 × t²

Hence, t² = 125/1.25 = 100

t = √(100) = 10 s

The equation for particle Q is v = 0 + 2.5×t

Hence, since particle P starts deceleration 6 seconds before the commencement of motion of particle Q, the amount of seconds after the commencement of deceleration of the first particle P that it takes for particle P to come to rest is found as follows;

Hence, at t = 6 + 10 = 16 seconds particle P speed = 25 m/s

From the equation of motion, for particle P (decelerating) we have

v = u - a·t

Where:

v = 25 m/s

u = 140 m/s

t = 16 s

Hence, 25 = 140 - a×16

∴ 16·a = 140 - 25 = 115

a = 115/16 = 7.1875 m/s²

Therefore, the time it takes before particle P comes to rest is found from the same equation of motion, where v = 0 as follows;

v = u - a·t

0 = 140 - 7.1875 × t

∴7.1875·t = 140

t = 140/7.1875 = 19.48 s ≈ 19.5 seconds.

4 0

3 years ago

1) A piano tuner is testing a wire currently under 2000 N tension. The wire is 1.5 m long and has a mass of 20 g. If the tuner's

m_a_m_a [10]

1.

Answer:

N = 77

Explanation:

1) As we know that Tension in the wire is given as

T = 2000 N

now mass per unit length of the wire is given as

$\frac{m}{L} = \frac{20 \times 10^{-3} kg}{1.5 m}$

$\frac{m}{L} = 0.013 kg/m$

Now fundamental frequency is given as

$f_o = \frac{1}{2L}\sqrt{\frac{T}{m/L}}$

$f_o = \frac{1}{2\times 1.5}\sqrt{\frac{2000}{0.013}}$

$f_o = 129 Hz$

now highest frequency is given as 10000 Hz

so total harmonics is given as

$N = \frac{10000}{129}$

$N = 77$

2.

Answer:

D) 7.14 Hz

Explanation:

As we know that

speed = (frequency)(wavelength)

given that

speed = 400 m/s

wavelength = 28 m

so frequency is given as

$f = \frac{400}{28}$

$f = 14.3 Hz$

now if wavelength is doubled then we will have

$wavelength = 56 m$

new frequency will be

$f = \frac{400}{56}$

$f = 7.14 hz$

3.

Answer:

Number of nodes = 4

A) 4

Explanation:

Number of nodes = number of harmonics + 1

so here we know that

number of harmonics = 3

Number of nodes = 3 + 1

Number of nodes = 4

4.

Answer:

C) 35.1 Hz

Explanation:

fundamental frequency in an organ pipe closed at one end is given as

$f = \frac{v}{4L}$

here we know that

v = 345 m/s

L = 2.46 m

now we have

$f = \frac{345}{4(2.46)}$

$f = 35.1 Hz$

5.

Answer:

A) 570

Explanation:

Number of harmonics is given as

$N = \frac{maximum :\frequency}{fundamental\: frequency}$

$N = \frac{20,000}{35.1}$

$N = 570$

6.

Answer:

$v = 37.12 m/s$

Explanation:

For fundamental frequency we know that

$f_o = \frac{v}{2L}$

here we know that

$f_o = 58 Hz$

$L = 32 cm$

now we have

$58 = \frac{v}{2(0.32)}$

$v = 37.12 m/s$

7 0

3 years ago