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2 years ago

How does a mutation in a gene affect a protein?

Physics

2 answers:

Olenka [21]2 years ago

3 0

Answer:

a variant can cause a protein to malfunction or to not be produced at all.

scoundrel [369]2 years ago

3 0

A mutation can cause a protein to not function properly or just not exist.

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8. Why might ChiN want to keep the price of the yuan low? Who suffers from this policy?

pychu [463]

Answer:

Experts claim that China is artificially keeping the Yuan low in order to get an unfair trade advantage.

Explanation:

3 0

2 years ago

In Fig., block 1 of mass m1 slides from rest along a frictionless ramp from height h = 2.50 m and then collides with stationary

Evgesh-ka [11]

Answer:

Explanation:

Given

initial height $h=2.5 m$

$m_2=2m_1$

coefficient of static friction $\mu =0.5$

When collision is elastic respective velocities after collision is

$v_1=\frac{u_1(m_1-m_2)+2m_2u_2}{m_1+m_2}$

$v_2=\frac{u_2(m_2-m_1)+2m_1u_1}{m_1+m_2}$

where $u_1$ and $u_2$ =initial velocities of object

$v_1$ and $v_2$ final velocities of object

$u_1=\sqrt{2\times 9.8\times 2.5}$

$u_1=7 m/s$

$v_2=\frac{0+2m_1\times 7}{m_1+2m_1}$

$v_2=\frac{14}{3} m/s$

using $v^2-u^2=2 as$

$0-(4.67)^2=2\times (-0.5\times 9.8)\times s$

$s=2.22\ m$

(b)Completely Inelastic

In Completely Inelastic objects stick with each other

$m_1u_1=(m_1+m_2)v$

$v=\frac{u_1}{3}=\frac{7}{3} m/s$

using $v^2-u^2=2 as$

$0-(2.33)^2=2\times (-0.5\times 9.8)\times s$

$s=0.55\ m$

7 0

4 years ago

The earth exerts a gravitational force on the moon. the moon exerts a gravitational force on the earth. how do the magnitudes of

Sonbull [250]

The forces are the same like the third law of Newton states.I think

3 0

3 years ago

If an object falls and ends with a velocity of 58.8 m/s, how long was the<br><br> object falling?

tensa zangetsu [6.8K]

Answer:

the time taken for the object to fall is 6 s.

Explanation:

Given;

final velocity of the object, v = 58.8 m/s

initial velocity of the object, u = 0

The height of fall of the object is calculated as;

v² = u² + 2gh

v² = 2gh

$h = \frac{v^2}{2g} \\\\h = \frac{(58.8)^2}{2(9.8)} \\\\h = 176.4 \ m$

The time to fall through the height is calculated as;

$h =ut+ \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\t= \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 176.4}{9.8} } \\\\t = 6 \ s$

Therefore, the time taken for the object to fall is 6 s.

6 0

3 years ago

When the diaphragm contracts , air pressure in the chest increases . True or False ?

nexus9112 [7]

Answer: False

When the diaphragm contracts, the muscles will also contract and pull upward and increase the size of the thoracic cavity thus decreases air pressure inside during inspiration. After the diaphragm contracts, it goes to relaxation, the muscles will also relaxed. It gets looser and return to its original position higher up in the chest. This increase the pressure in the chest, which force the air in the lungs out through the nose.

6 0

3 years ago

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