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3 years ago

Kyle is flying a helicopter and is rising at 5.0m/s when he releases the bag. After 2.0s

Physics

2 answers:

ELEN [110]3 years ago

8 0

A. What is the bag’s velocity?
Answer: 25 m/s

b. How far has the bag fallen?
Answer: -30 m

c. How far below the helicopter is the bag?
Answer: 20 m below the helicopter

ch4aika [34]3 years ago

5 0

1) v=u+gt = -5 +10*2=15 m/s
2) r=ut+gt^2/2=-5*2+10*2^2/2=-10+20=10m
3) r of heli= vt =5*2=10m
So 10m by bag from answer number 2 plus additional 10m by helicopter equals 20m

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c) goalie

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Una onda tiene una frecuencia de 350 Hz. ¿Cuál es su período?

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3 years ago

A ball is dropped from rest at point O. After falling for some time, it passes by a window of height 3.3 m and it does so in 0.2

stiv31 [10]

Answer:

Speed at which the ball passes the window’s top = 10.89 m/s

Explanation:

Height of window = 3.3 m

Time took to cover window = 0.27 s

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We have equation of motion s = ut + 0.5at²

For the top of window (position A)

$s_A=0\times t_A+0.5\times 9.81t_A^2\\\\s_A=4.905t_A^2$

For the bottom of window (position B)

$s_B=0\times t_B+0.5\times 9.81t_B^2\\\\s_A=4.905t_B^2$

$\texttt{Height of window=}s_B-s_A=3.3\\\\4.905t_B^2-4.905t_A^2=3.3\\\\t_B^2-t_A^2=0.673$

We also have

$t_B-t_A=0.27$

Solving

$t_B=0.27+t_A\\\\(0.27+t_A)^2-t_A^2=0.673\\\\t_A^2+0.54t_A+0.0729-t_A^2=0.673\\\\t_A=1.11s\\\\t_B=0.27+1.11=1.38s$

So after 1.11 seconds ball reaches at top of window,

We have equation of motion v = u + at

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Speed at which the ball passes the window’s top = 10.89 m/s

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3 years ago

As you move farther away from a source emitting a pure tone, the ___________ of the sound you hear decreases.

Colt1911 [192]

Answer:

frequency

Explanation:

The phenomenon of apparent change in frequency due to the relation motion between the source and the observer is called Doppler's effect.

So, when we move farther, the frequency of sound decreases. The formula of the Doppler's effect is

$f' = \frac{v + v_o}{v+ v_s} f$

where, v is the velocity of sound, vs is the velocity of source and vo is the velocity of observer, f is the true frequency. f' is the apparent frequency.

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2 years ago

A football is kicked from ground level at an angle of 53 degrees. It reaches a maximum height of 7.8 meters before returning to

Nonamiya [84]

Answer:

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Let u be the velocity of projection.

The formula for maximum height is given by