THE ANSWER IS D. A NONMETAL ATOM TRANSFERS ELCTRONS TO A METAL ATOM
ITS A TYPE OF ENERGY BONDING THAT ARISES FROM ELECTROSTATIC. ATTRACTIVE FORCE BETWEEN CONDUCTION ELCTRONS (A NONMETAL ATOM) AND A POSITIVELY CHARGED METAL ATOM ( WHO ATTRACTS THE NONMETALS ELECTRONS BECAUSE ITS POSITIVELY CHARGED)
Answer:
The required steady force of each rocket is 28.79 N
Explanation:
mass of the satellite, M=3900 kg
radius, r=4.3 m
mass of rocket, m=210 kg
time, t=5.4 min
Moment of Inertia:
I = 1/2 (Mr^2) + 4mr^2
I = 1/2 ( 3900* (4.3)^2) + 4 (210)*(4.3)^2
I = 51587.1 kg m^2
the angular acceleration is:
a= w/t
here w= 2*π*30
so,
a= 2*π*30 / 5.4* 3600
a=0.0096 rad/ s^2
the Torque becomes:
T=I*a = 4r*F
( 51587.1 )*(0.0096) = 4*4.3* F
F= 28.79 N
the required steady force of each rocket is 28.79 N
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Answer:
1500 Joules
Explanation:
Work = Force x Distance
When multiplying by 10 you simply shift all the digits to the
left and append a 0 to the end.
so 150 x 10 = 1500 Joules
Answer:
0.7757 rev/s
Explanation:
d = Diameter of the tornado = 53 m
r = Radius of the tornado = 53/2 = 26.5 m
v = Velocity of wind = 465 km/h
Converting velocity to m/s
Angular velocity
∴ Angular velocity is 0.7757 rev/s
Answer: 5,640 s (94 minutes)
Explanation:
the tangential speed of the HST is given by
(1)
where
is the length of the orbit
r is the radius of the orbit
T is the orbital period
In our problem, we know the tangential speed: 
. The radius of the orbit is the sum of the Earth's radius and the distance of the HST above Earth's surface:
So, we can re-arrange equation (1) to find the orbital period:
Dividing by 60, we get that this time corresponds to 94 minutes.
