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3 years ago

15

Find the steady-state temperature distribution for the semi-infinite plate problem

1 answer:

jeka943 years ago

6 0

Answer:

Savage is the answer

Explanation: The savage people guess like me

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How does the loneliest whale relate to physics/waves.

Lelechka [254]

Answer: the loneliest whale relates to the communication that whales give to each other

Explanation: whales have different forms of communication , and the ‘loneliest’ whale can’t get any company by the other whales.

In other words: it may be a new and different way whales communicate, nobody knows much about the loneliest whale. It may be forming a new kind of communication

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3 years ago

What happens to the force of gravity between two masses if one mass is decreased?

Andrews [41]

<span>B. It stays the same</span>

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3 years ago

Read 2 more answers

What is linear momemtum

Genrish500 [490]

Answer:

Its momentum thats linear

Explanation:

from my secret analysis i would say this is really linear

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2 years ago

People who view society as a set of interrelated parts that work together to produce a stable social system are said to employ t

AURORKA [14]

The answer is d. functionalist perspective

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3 years ago

A car travels at a steady 40.0 m/s around a horizontal curve of radius 200 m. What is the minimumcoefficient of static friction

zhenek [66]

Answer:

c. 0.816

Explanation:

Let the mass of car be 'm' and coefficient of static friction be 'μ'.

Given:

Speed of the car (v) = 40.0 m/s

Radius of the curve (R) = 200 m

As the car is making a circular turn, the force acting on it is centripetal force which is given as:

Centripetal force is, $F_c=\frac{mv^2}{R}$

The frictional force is given as:

Friction = Normal force × Coefficient of static friction

$f=\mu N$

As there is no vertical motion, therefore, $N=mg$ . So,

$f=\mu mg$

Now, the centripetal force is provided by the frictional force. Therefore,

Frictional force = Centripetal force

$f=F_c\\\\\mu mg=\frac{mv^2}{R}\\\\\mu=\frac{v^2}{Rg}$

Plug in the given values and solve for 'μ'. This gives,

$\mu = \frac{(40\ m/s)^2}{200\ m\times 9.8\ m/s^2}\\\\\mu=\frac{1600\ m^2/s^2}{1960\ m^2/s^2}\\\\\mu=0.816$

Therefore, option (c) is correct.

7 0

3 years ago