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3 years ago

What is true about isolines on a weather map?

Physics

2 answers:

vlabodo [156]3 years ago

6 0

Answer: Hi, isolines refer to lines where some quantity maintains constant.

For example, an "istoremal line" is a line where the temperature is constant, an "isobaric line" is a line where the pressure is constant.

Where constant means that, in the two examples i give you, in all the line the temperature or the pressure has the same value.

A thing that you usually can see in a whether map, is that the isolines are "closed" curves. And other thing, maybe more obvious, is that a line cant pass over other line (because this will mean that a point in the space has 2 different values of something).

Law Incorporation [45]3 years ago

5 0

All isolines, or iso-intensity lines, connect points having equal values.

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A closed space zone is one that is obstrutced in some way.

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The chart below shows the average surface temperature or temperature range for each of the eight planets.

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Answer:

A) Earth and the other inner planets have higher average surface temperatures than the outer planets.

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the earth and the other inner planets have higher average surface temperatures than the outer planets.

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The sales price of a product is $2 per unit; the variable cost is $1 per unit; and fixed costs total $1,000. how many units must

irakobra [83]

Answer:

1000 units for breakeven

Explanation:

Let x be the number of units sold at breakeven.

The total sales at the point would be $2x.

Variable costs would be $1x and fixed costs are $1000.

Total costs are = $1x + $1000

At breakeven: Sales = Costs

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2 years ago

A 0.560 kg snowball is fired from a cliff 14.2 m high with an initial velocity of 13.3 m/s, directed 26.0° above the horizontal.

enot [183]

Answer:

a) v = 21.34 m/s

b) v = 21.34 m/s

c) v = 21.34 m/s

Explanation:

Mass of the snowball, m = 0.560 kg

Height of the cliff, h = 14.2 m

Initial velocity of the ball, u = 13.3 m/s

θ = 26°

The speed of the slow ball as it reaches the ground, v = ?

The initial Kinetic energy of the snow ball, $KE_{0} = 0.5 mu^{2}$

Potential energy of the snow ball at the given height, PE = mgh

Final Kinetic energy of the ball as it reaches the ground, $KE_{f} = 0.5mv^{2}$

a) Using the principle of energy conservation,

$KE_{0} + PE = KE_{f} \\0.5mu^{2} + mgh = 0.5mv^{2}\\v^{2} =2( 0.5u^{2} + gh)\\v^{2} =u^{2} + 2gh\\v = \sqrt{u^{2} + 2gh} \\v = \sqrt{13.3^{2} + 2*9.8*14.2}\\v = 21.34 m/s$

b) The speed remains v = 21.34 m/s since it is not a function of the angle of launch

c)The principle of energy conservation used cancels out the mass of the object, therefore the speed is not dependent on mass

v = 21. 34 m/s

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3 years ago