Explanation:
F = 20N m= m1 a=10m/s²
m=m2 a=5m/s²
F = ma
<u>for the first one</u><u>:</u><u> </u>
f=m1 × a
20 = m1 ×10
20=10m1
m1=20/10
m1=2
<u>for</u><u> </u><u>the</u><u> </u><u>second</u><u> </u><u>one</u><u> </u><u>:</u>
f=m2×a
20=m2×5
m2= 20/5
m2= 4
since F=ma
F=(m1+m2) ×a
F =(4+2)×a
F =6×a
F=20(from the question above )
20=6×a
a=20/6
a=3.33
Momentum would be the same before and after the collision
Before the collision:
Momentum of the single cart: 1 * 0.50 = 0.50
After the collision
velocity = 0.25m / s
1 * 0.25 + 1 * 0.25 =
0.25 * (1 + 1) =
0.25 * 2 =
0.50
Now new momentum will be 0.5
answer
the same before and after the collision
Answer:
a)3312 x 10⁴ J
b)I = 57.5 A
c)9200 W
Explanation:
Given that
P =4600 W
Time t= 2 h = 2 x 3600 s= 7200 s
We know that
1 W = 1 J/s
a)
Energy stored in the battery = P .t
=4600 x 7200 J
=3312 x 10⁴ J
b)
We know that power P given as
P = V .I
V=Voltage ,I =Current
4600 = 80 x I
I = 57.5 A
c)
The energy supplied = 4600 x 2 = 9200 W
