Answer: Within any frame of reference that is accelerating
Special relativity was proposed on 1905 by Einstein, who developed his theory based on the following two postulates:
1. <em>The laws of physics are the same in all inertial systems. There is no preferential system.
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2. <em>The speed of light in vacuum has the same value for all inertial systems.
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Focusing on the first postulate, it can be affirmed that <u>any measurement on a body is made with reference to the system in which it is being measured</u>.
Now, taking into account that an inertial reference system is the one that complies with the principle of inertia:
<em>"For a body to have acceleration, an external force must act on it."</em>
The correct answer is
Within any frame of reference that is accelerating
d. The amount of work will increase.
Explanation:
If the distance traveled is increased and other factors are kept constant, then the amount of work done will increase.
- For is a product of force and distance.
Work done = Force x distance
- This shows that force and distance are directly related to work done.
- A change in any of the two product will change the value of work done.
- The unit of work done is Joules
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Answer:
0.0083km or 8.3m
Explanation:
Given parameters:
Distance = 5km
Time = 10min
Unknown:
Distance moved in 1sec = ?
Solution:
To solve this problem, let us first find the speed of the motorbike.
Speed =
Speed = = 0.5km/min
So;
In 1sec:
60 sec = 1 min
1 sec = min
Distance moved in 1sec = speed x time
Distance moved = 0.5km/min x min = 0.0083km or 8.3m
The density of the metal is important because if its more dense than water it will sink but if its lighter than water it will float
Answer: Option C) 11.25 A
Explanation:
Given that:
Voltage V = 90 volts
total current I = ?
Three resistors each with 40 Ω, 30 Ω, and 15 Ω in parallel, the equivalent resistance of the combination (Rtotal) of the circuit is as follows:
i.e 1/Rtotal = (1/R1 + 1/R2 + 1/R3)
1/Rtotal = (1/40Ω + 1/30Ω + 1/15Ω)
1/Rtotal = (3 + 4 + 8)/120Ω
1/Rtotal = 15/120Ω
1/Rtotal = 1/8Ω
To get the value of Rtotal, cross multiply
Rtotal x 1 = 8Ω x 1
Rtotal = 8Ω
Then, apply the formula V = I x Rtotal
90 volts = I x 8Ω
I = 90 volts / 8Ω
I = 11.25 Amperes
Thus, the total current used by the three lamps is 11.25 Amperes