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Sergeu [11.5K]
3 years ago
7

Express 9.39x10^9 seconds in terms of days

Physics
2 answers:
natka813 [3]3 years ago
6 0

Answer:

There is an error in the answer before. 9.39 x 10^9 seconds is 108680.56 days

Explanation:

The reason is you have to convert, from seconds, to minutes, then to hours and then to days.

To minutes, you divide by 60.

9390000000/6 = 1565000000 minutes

From minutes to hours, divide by 60

1565000000/60=26083333.334

Finally, from hour to days, divide by 24

26083333.334/24=1086805.56

LenaWriter [7]3 years ago
3 0
First we figure out how many seconds that is

9,390,000,000

then divide by 60 to get how many hours that is<span>
</span>
156,500,000

now divide by 24 to get the number of days

6520833 and 1/3

that is how many days it is



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A parallel plate capacitor creates a uniform electric field of and its plates are separated by . A proton is placed at rest next
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Complete Question

A parallel plate capacitor creates a uniform electric field of 5 x 10^4 N/C and its plates are separated by 2 x 10^{-3}'m. A proton is placed at rest next to the positive plate and then released and moves toward the negative plate. When the proton arrives at the negative plate, what is its speed?

Answer:

V=1.4*10^5m/s

Explanation:

From the question we are told that:

Electric field B=1.5*10N/C

Distance d=2 x 10^{-3}

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Generally the equation for Velocity is mathematically given by

V^2=2as

Therefore

V^2=\frac{2*e_0E*d}{m}

V^2=\frac{2*1.6*10^{-19}(5*10^4)*2 * 10^{-3}}{1.67*10^{-28}}

V=\sqrt{19.2*10^9}

V=1.4*10^5m/s

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3 years ago
An Olympic high jumper, with a mass of 82 kg, has a
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2 years ago
A spaceship from a friendly, extragalactic planet flies toward Earth at 0.203 0.203 times the speed of light and shines a powerf
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The velocity of the transverse waves produced by an earthquake is 5.05 km/s, while that of the longitudinal waves is 8.585 km/s.
sattari [20]

Answer:

d=691.71km

Explanation:

The time lag between the arrival of transverse waves and the arrival of the longitudinal waves is defined as:

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Here d is the distance at which the earthquake take place and v_t, v_l is the velocity of the transverse waves and longitudinal waves respectively. Solving for d:

t=d(\frac{1}{v_t}-\frac{1}{v_l})\\d=\frac{t}{\frac{1}{v_t}-\frac{1}{v_l}}\\d=\frac{56.4s}{\frac{1}{5.05\frac{km}{s}}-\frac{1}{8.585\frac{km}{s}}}\\d=691.71km

8 0
3 years ago
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