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Strike441 [17]
1 year ago
7

______ resources include biodiversity, energy, land and soil, and water resources.

Physics
2 answers:
cluponka [151]1 year ago
7 0
Natural resources!

Explanation:
Natural resources are the resources that are not manmade. They were made by nature. Example: water, soil, energy, land, biodiversity. None of these can be made by mankind, therefore they are natural resources
cricket20 [7]1 year ago
5 0

Answer : <u>Natural</u>

Explanation : Natural resources are the resources that are found in the environment and are developed without the intervention of humans

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A 1200 kg car accelerates from rest for 45 meters in 6.0 seconds. What is the net force on the car?​
Alja [10]

Answer:

Explanation:

At first, you have to get the acceleration value from the given data.

s=ut+\frac{1}{2}at^{2}

s= 45m

u= 0 m/s

t = 6s

a = ?

45 = 0+ 0.5 × a × 6²

45 = 0.5 × 36 × a

45 = 18a

a = 2.5 m/s²

Now, you can use F=ma equation

F = ?

m = 1200kg

a = 2.5 m/s²

F = 1200 × 2.5

F = 3000 N

8 0
4 years ago
Calculation using Ohm's Law: If a circuit has a voltage of 500 V and a resistance of 250 ohms, what is the current?
konstantin123 [22]

I = V / R

Current = (voltage) / (resistance)

Current = (500 V) / (250 ohms)

Current = (500/250) Amperes

<em>Current = 2 Amperes</em>

6 0
3 years ago
Read 2 more answers
Find h , the maximum height attained by the projectile. express the maximum height in terms of v 0 , θ , and g .
lutik1710 [3]

solution:

the utmost height would be comprehensive while y'(t)=0. (on the suitable of the trajectory, the y speed is 0.)y(t)=(88sin20)t-16t^2 y'(t)=88sin20-32t So y'(t)=0 while t=(88sin20)/32

3 0
4 years ago
Hello please help i’ll give brainliest
andriy [413]

Answer:

It should be (A few centimeters per year) About three to five centimeters

5 0
3 years ago
A 0.70-kg disk with a rotational inertia given by MR 2/2 is free to rotate on a fixed horizontal axis suspended from the ceiling
Setler [38]

Answer:

The force will be "9.8 N".

Explanation:

The given values are:

mass,

m = 0.7 kg

M = 2

g = 9.8

Now,

⇒  \tau = T \alpha

then,

⇒  \frac{1}{2}mR^2(\frac{1}{R}\frac{dv}{dt}) =M(g-a_t)R

⇒  \frac{1}{2}m \ a_t=m(g-a_t)

⇒  a_t=\frac{2g}{(\frac{m}{M} +2)}

On substituting the values, we get

⇒      =\frac{2\times 9.8}{\frac{0.7}{2} +2}

⇒      =8.34 \ m/s

hence,

⇒  T=mg+M(g-a_t)

On substituting the values, we get

⇒      =0.7\times 9.8+2(9.8-8.34)

⇒      =6.86+2(1.46)

⇒      =6.86+2.92

⇒      =9.8 \ N

5 0
3 years ago
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