Answer:
Explanation:
At first, you have to get the acceleration value from the given data.

s= 45m
u= 0 m/s
t = 6s
a = ?
45 = 0+ 0.5 × a × 6²
45 = 0.5 × 36 × a
45 = 18a
a = 2.5 m/s²
Now, you can use F=ma equation
F = ?
m = 1200kg
a = 2.5 m/s²
F = 1200 × 2.5
F = 3000 N
I = V / R
Current = (voltage) / (resistance)
Current = (500 V) / (250 ohms)
Current = (500/250) Amperes
<em>Current = 2 Amperes</em>
solution:
the utmost height would be comprehensive while y'(t)=0. (on the suitable of the trajectory, the y speed is 0.)
Answer:
It should be (A few centimeters per year) About three to five centimeters
Answer:
The force will be "9.8 N".
Explanation:
The given values are:
mass,
m = 0.7 kg
M = 2
g = 9.8
Now,
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then,
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On substituting the values, we get
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hence,
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On substituting the values, we get
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