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ryzh [129]
3 years ago
11

If you were to drop a rock from a tall building, assuming that it had not yet hit the ground, and neglecting air resistance. Wha

t is its vertical displacement (in m) after 8 s? (g = 10 m/s2)
Physics
1 answer:
Marizza181 [45]3 years ago
5 0

Answer:

320m

Explanation:

The vertical displacement is given by:

y_0-y=\frac{1}{2}gt^2-v_0t

Assuming v₀=0, t=8:

y_0-y=\frac{10}{2} \times 8^2 + 0\times 8 = 320

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50 POINTS
strojnjashka [21]

Answer:   A    Answers. Assuming that the terminal velocity doesn't change during the fall, then the kinetic energy would remain constant. However the terminal velocity decreases during the fall since the air becomes denser at lower altitudes.

Explanation:

What happens to the KE of an object when it slows down and heats up? - Quora. The kinetic energy goes down and the loss of the kinetic energy is through the production of heat energy. In real world this is due to friction, or an opposing force that decelerates the object, or a combination of both.

8 0
3 years ago
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A carnival game consists of a two masses on a curved frictionless track, as pictured below. The player pushes the larger object
Harman [31]

Answer:

v₁₀ = 1.90 m / s

Explanation:

In this exercise we are given the maximum height data, with energy we can know how fast the body came out

Final mechanical energy, maximum height

    Em_{f} = U = m g h

Initial mechanical energy, in the lower part of the track

    Em₀ = K = ½ m v²

    Em=   Em_{f}

    ½ m v² = m g h

    v = √ 2gh

Now we can use the moment to find the speed with which objects collide

The large object has a mass M = 5.41 kg a velocity starts v₁₀, the small object has a mass m = 1.68 kg an initial velocity of zero v₂₀ = 0 and  final velocity v

Initial before the crash

    p₀ = M v₁₀ + 0

Final after the crash

      p_{f} = M v1f + m v

   p₀ =   p_{f}

   M v₁₀ = M v_{1f}+ m v

As the shock is elastic the kinetic energy is conserved

     K₀ = K_{f}

    ½ M v₁₀² = ½ M v_{1f}² + ½ m v²

Let's write the system of equations

    M v₁₀ = M  v_{1f} + m v

    M v1₁₀² = M v_{1f}² + m v²

We cleared v1f in the first we replaced in the second

   v_{1f} = (M v₁₀ - mv) / M

    M v₁₀² = M (M v₁₀ - mv)² / M² + m v²

    M v₁₀² = 1 / M (M² v₁₀² - 2mM v v₁₀ + m² v²) +m v²

     v₁₀² (M - M) + 2 m v v₁₀ - v² (m2 + m) / M = 0

     2 m v₁₀ - v (m + 1) m/ M = 0

     v₁₀ = v (m +1) / (2M)

Let's substitute the value of v

     v1₁₀= √ (2gh) (m +1) / (2M)

Let's calculate

    v₁₀ = √ (2 9.8 3) (1+ 1.68) / (2  5.41)

    V₁₀ = 7.668 (2.68) / 10.82

   v₁₀ = 1.90 m / s

5 0
3 years ago
Please help me with question B.
Step2247 [10]
It accelerates in the y component (bc of gravity) AND the x-component (b/c of the friction force).
5 0
3 years ago
After watching a show about submarines, Jamil wants to learn more about the oceans. Which question could be answered through sci
lyudmila [28]
He can ask what substances dissolve in ocean water. 
6 0
3 years ago
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Which temperature scale has no negative temperatures A. Celsius B. Joule C. Fahrenheit D. Kelvin
Brilliant_brown [7]
The Kelvin scale has no negatives on it.

Zero Kelvin is 'Absolute Zero', and nothing can get colder than that.
6 0
3 years ago
Read 2 more answers
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