Question

If you were to drop a rock from a tall building, assuming that it had not yet hit the ground, and neglecting air resistance. What is its vertical displacement (in m) after 8 s? (g = 10 m/s2)

Answer 1

Answer:

320m

Explanation:

The vertical displacement is given by:

$y_0-y=\frac{1}{2}gt^2-v_0t$

Assuming v₀=0, t=8:

$y_0-y=\frac{10}{2} \times 8^2 + 0\times 8 = 320$