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ryzh [129]
3 years ago
11

If you were to drop a rock from a tall building, assuming that it had not yet hit the ground, and neglecting air resistance. Wha

t is its vertical displacement (in m) after 8 s? (g = 10 m/s2)
Physics
1 answer:
Marizza181 [45]3 years ago
5 0

Answer:

320m

Explanation:

The vertical displacement is given by:

y_0-y=\frac{1}{2}gt^2-v_0t

Assuming v₀=0, t=8:

y_0-y=\frac{10}{2} \times 8^2 + 0\times 8 = 320

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The loudness of a sound is the waves amplitude <br><br><br><br> True or false
kakasveta [241]

Answer:

true i think

Explanation:

The amplitude of a sound wave determines its loudness or volume. A larger amplitude means a louder sound, and a smaller amplitude means a softer sound. In Figure 10.2 sound C is louder than sound B. The vibration of a source sets the amplitude of a wave.

4 0
2 years ago
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A child drops a ball from a window.The ball strikes the ground in 3.0 seconds.What is the velocity of the ball the instant befor
lord [1]
It might be 4.0 or 2.22344 seconds as velocity speed
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According to Binet, mental age relates to chronological age because ___________.
mamaluj [8]
<em>Its B fam, hope you get that good grade.</em>
8 0
3 years ago
The parallel plates in a capacitor, with a plate area of 8.00 cm2 and an air-filled separation of 2.70 mm, are charged by a 8.70
MrRa [10]

Answer:

a)  ΔV₁ = 21.9 V, b) U₀ = 99.2 10⁻¹² J, c) U_f = 249.9 10⁻¹² J,  d)  W = 150 10⁻¹² J

Explanation:

Let's find the capacitance of the capacitor

         C = \epsilon_o \frac{A}{d}

         C = 8.85 10⁻¹² (8.00 10⁻⁴) /2.70 10⁻³

         C = 2.62 10⁻¹² F

for the initial data let's look for the accumulated charge on the plates

          C = \frac{Q}{\Delta V}

          Q₀ = C ΔV

           Q₀ = 2.62 10⁻¹² 8.70

           Q₀ = 22.8 10⁻¹² C

a) we look for the capacity for the new distance

          C₁ = 8.85 10⁻¹² (8.00 10⁻⁴) /6⁴.80 10⁻³

          C₁ = 1.04 10⁻¹² F

       

          C₁ = Q₀ / ΔV₁

          ΔV₁ = Q₀ / C₁

          ΔV₁ = 22.8 10⁻¹² /1.04 10⁻¹²

          ΔV₁ = 21.9 V

b) initial stored energy

          U₀ = \frac{Q_o}{ 2C}

          U₀ = (22.8 10⁻¹²)²/(2  2.62 10⁻¹²)

          U₀ = 99.2 10⁻¹² J

c) final stored energy

          U_f = (22.8 10⁻¹²) ² /(2  1.04 10⁻⁻¹²)

          U_f = 249.9 10⁻¹² J

d) the work of separating the plates

as energy is conserved work must be equal to energy change

          W = U_f - U₀

          W = (249.2 - 99.2) 10⁻¹²

          W = 150 10⁻¹² J

note that as the energy increases the work must be supplied to the system

6 0
3 years ago
What happens to acceleration if forces are balanced
Vikentia [17]

Answer:

No acceleration.

Explanation:

If the forces are Balanced it means they are in equilibrium and there will be  no net force, therefore the object will not accelerate and the velocity will remain constant.

5 0
3 years ago
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