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ryzh [129]
3 years ago
11

If you were to drop a rock from a tall building, assuming that it had not yet hit the ground, and neglecting air resistance. Wha

t is its vertical displacement (in m) after 8 s? (g = 10 m/s2)
Physics
1 answer:
Marizza181 [45]3 years ago
5 0

Answer:

320m

Explanation:

The vertical displacement is given by:

y_0-y=\frac{1}{2}gt^2-v_0t

Assuming v₀=0, t=8:

y_0-y=\frac{10}{2} \times 8^2 + 0\times 8 = 320

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Red light from three separate sources passes through a diffraction grating with 5.60×105 slits/m. The wavelengths of the three l
shtirl [24]

Answer:

I can help

Explanation:

6 0
3 years ago
our 3.80-kg physics book is placed next to you on the horizontal seat of your car. The coefficient of static friction between th
gtnhenbr [62]

Answer:

Explanation:

Maximum force of friction possible = μmg

= .65 x 3.8 x 9.8

= 24.2 N

u = 72 x 1000 / 60 x 60

= 20 m /s

v² = u² - 2as

a = 20 x 20 / (2 x 30)

= 6.67 m / s²

force acting on it

= 3.8 x 6.67

= 25.346 N

Friction force possible is less .

So friction will not be able to prevent its slippage

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4 0
3 years ago
A force of 14 N acts on a 5 kg object for 3 seconds.
DiKsa [7]

Answer: a) 42Nm b) 8.4m/s

Explanation:

Impulse is defined as object change in momentum.

Since Force = mass × acceleration

F = ma

Acceleration is the rate of change in velocity.

F = m(v-u)/t

Cross multiply

Ft = m(v-u)

Since impulse = Ft

and Ft = m(v-u)... (1)

The object change in velocity (v-u) = Ft/m from eqn 1

Going to the question;

a) Impulse = Force (F) × time(t)

Given force = 14N and time = 3seconds

Impulse = 14×3

Impulse = 42Nm

b) The object change in velocity (v-u) = Ft/m where mass = 5kg

v-u = 14×3/5

Change in velocity = 42/5 = 8.4m/s

3 0
3 years ago
2. An alternating current is represented by the equation I=20sin 100mt.
Sladkaya [172]

Explanation:

The general equation of an AC current is given by :

I=I_o sin\omega t

Where

I₀ is the peak value of current

\omega is angular frequency

As\ \omega=2\pi f

So,

f=\dfrac{\omega}{2\pi}\\\\f=\dfrac{100\pi}{2\pi}\\\\f=50\ Hz

We know that,

I_{rms}=\dfrac{I_0}{\sqrt{2}}\\\\=\dfrac{20}{\sqrt{2}}\\\\I_{rms}=14.14\ A

So, the frequency is 50 Hz and the maximum rms value of current is 14.14 A.

3 0
3 years ago
What is the streak of a mineral used for
ad-work [718]

The streak of a mineral is used for identifying what the mineral may be.

Hope this helps :)

5 0
3 years ago
Read 2 more answers
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