Number 5 goes to letter e
Answer:
155.17N.
Explanation:
The magnitude of the net force is expressed as;
F = mv²/r where;
m is the mass
v is the velocity of the airplane
r is the radius of the loop
Given
m = 95kg
v = 70m/s
r = 3km = 3000m
Required
Magnitude of the net force
F = 95*70²/3000
F = 95*4900/3000
F = 95*49/30
F = 4655/30
F = 155.17N
Hence the magnitude of the net force on the 95 kg pilot at the bottom of this loop is 155.17N.
Answer:
C It will be closer to the mass of Vi–193.
Explanation:
The average atomic mass of vitellium will be closer to the mass of Vi–193.
From the geonormal abundance we can derive the average atomic mass or relative atomic mass of the compound.
Average atomic mass = sum of all the product of the mass of isotope x abundance of isotope
Average atomic mass = (10.861% x 187.9122) + (12.428% x 190.9047) + (76.11% x 192.8938)
Average atomic mass = 20.41 + 23.73 + 146.81 = 190.95amu
Answer:A
Explanation: number that shows the total atomic mass of the substance