The volume that will be at 2.75 atm with constant temperature and molar amount is calculated using bolyes law formula that is P1V1=P2V2
P1=1.05 atm
V1=3.78 L
P2=2.75 atm
v2=?
by making V2 the subject of the formula V2= P1V1/P2
= 3.78 L x 1.05 atm/ 2.75 atm =1.44 L
The magnitude of the force required to change the length of a spring-like object is directly proportional to the spring constant and the displacement of the spring. Elastic potential energy is directly proportional to the square of the change in length and the spring constant.
Answer:
Explanation:The final homogenous solution, after cooling it to 40°C, will contain 47 g of potassium sulfate disolved in 150 g of water, so you can calculate the amount disolved per 100 g of water in this way:
[47 g of solute / 150 g of water] * 100 g of g of water = 31.33 grams of solute in 100 g of water.
So, when you compare with the solutiblity, 15 g of solute / 100 g of water, you realize that the solution has more solute dissolved with means that it is supersaturated.
To make a saturated solution, 15 grams of potassium sulfate would dissolve in 100 g of water.
Read more on Brainly.com - brainly.com/question/5143785#readmore
Answer:
7.506 g
Explanation:
In order to answer the first question we need to keep in mind the requested concentration of acetate: 0.250 M. With the concentration and the volume we can calculate the required moles and then the required grams:
0.250 M * 0.500 L = 0.125 moles acetate
0.125 moles * 60.05 g/mol = 7.506 g
So 7.506 g of acetic acid will be needed to prepare the buffer.
Answer:
I am not sure but I will say 5625
Explanation:
