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Scrat [10]
3 years ago
14

(PLEASE HELP)simplify 2 with an exponent of 5 over 3 with an exponent of 2 and the equation has an exponent of 4

Mathematics
1 answer:
Nostrana [21]3 years ago
4 0
Assuming you mean this as your problem I hope I can assist you.
( \frac{2^5}{3^2})^4
So just apply the exponent rule to start, which is (a/b)^c = a^c/b^c
This translates to....
\frac{(2^5)^4}{(3^2)^4}
Now apply the exponent rule (a^b)^c = a^bc
Which translates to 3^2 * 4 which is refined to 3^8
So now we have....
\frac{(2^5)^4}{3^8}
Just apply the exponent rule (a^b)^c
So we get 2^5 * 4 which refines to 2^20
Therefore our final answer is 2^20/3^8


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|18-x|, if x<18. Pls help
damaskus [11]

Answer:

I18 - xI such that x < 18.

ok, first let's what happens if x = 18:

I18 - xI = I18 - 18I = 0

So, at the moment we have the condition:

I18 - xI > 0.

now, if x is a really large negative number, suppose, x = -100

I18 + 100I = I118I = 118

So, as x can freely move in the negative range, we can see that I18 - xI can be any positive number, so the only restriction that we have is:

I18 - xI > 0.

This means that the domain is:

D = (-∞, 18)

and the range is:

R = (0, ∞)

3 0
3 years ago
Try to to solve it please 2021 lets gooo​
ch4aika [34]

1.When all the three cut outs of the angles A, B, C placed adjacent to each other at a point, then it forms a line forming a straight angle, i.e. 180°.

Flence, it is proved that the sum of the three angles of a triangle is 180°.

Therefore, ∠A + ∠B + ∠C =180

5 0
3 years ago
Read 2 more answers
Please help! Solve for a.
Marat540 [252]
What am I solving? Like what is the question?
3 0
3 years ago
Darrel divided 575 by 14 by using partial quotients. What is quotient and explain answer using numbers and words
RideAnS [48]
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4 0
3 years ago
Which inequality is equivalent to x-6/x+5≥x+7/x+3?
yawa3891 [41]
To find equivalent inequalities you have to work the inequality given.

The first step is transpose on of sides to have an expression in one side and zero in the other side:

  x - 6        x + 7
--------- ≥  --------
  x + 5       x + 3

=>

  x - 6          x + 7
--------- -  --------   ≥ 0
  x + 5       x + 3

=>

 (x - 6) (x + 3) - (x + 7) (x + 5)
--------------------------------------- ≥ 0
          (x + 5) (x + 3)

=>

 x^2 - 3x - 18 - x^2 - 12x - 35
--------------------------------------- ≥ 0
         (x + 5) (x + 3)

           15x + 53
-     -------------------   ≥ 0
       (x + 5) (x + 3)

That is an equivalent inequality. Sure you can arrange it to find many other equivalent inequalities. That is why you should include the list of choices. Anyway from this point it should be pretty straigth to arrange the terms until making the equivalent as per the options.
4 0
3 years ago
Read 2 more answers
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