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melomori [17]
4 years ago
13

What is the solution of the following system of equations ? y- 2x and= 6 , y - 4x =0

Mathematics
1 answer:
Sveta_85 [38]4 years ago
6 0

Answer:

x=3 and y=12

Step-by-step explanation:

y-2x=6     equation:1

y-4x=0     equation:2

Solving equation:1 for 'y' in terms of x

y=6+2x      equation:3

Putting 'y' in equation:2 which will make the equation of the single variable

y-4x=0

6+2x-4x=0\\-2x=-6\\x=3

Putting value of 'x' in equation:3 to find 'y'

y=6+2x

y=6+2(3)\\y=6+6\\y=12

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I need help what is the answer plz
dlinn [17]

Answer:

-2.25

Step-by-step explanation:

Since there are 4 ticks between 2 numbers, we do 1/4 = 0.25

Now we find the value:

-2.25

8 0
3 years ago
Ok some one ask me what 20 + 20 - 20 is said its 20 e didnt belive me i know thats the right anser
postnew [5]

Answer:

it is because 20 + 20 is 40 and then 40 - 20 = 20

6 0
3 years ago
During Samuel’s experiment, the experimental probability was 0.25. What else must be true about the experiment?
antiseptic1488 [7]

Answer:

The experimental probability of the outcome is 1/4

Step-by-step explanation:

If Samuel's experiment probability was 0.25, this depicts that the experimental probability of the outcome is 1/4, because:

1/4=0.25

It's not the theoretical probability, because Samuel's developed an experiment, it cannot be theoretical, he has experimental evidences.

5 0
3 years ago
Read 3 more answers
You operate a gaming Web site, www.mudbeast.net, where users must pay a small fee to log on. When you charged $3 the demand was
Doss [256]

Answer:

A) The linear relation between price and demand is:

d=-550x+2750

The revenue R is:

R=-550x^2+2750x

B) The profit functionP is:

P=-550x^2+2750x-30

C) The largest monthly profit is obtained with a log-on fee of $2.5 per month. This corresponds to a profit of $3407.5.

Step-by-step explanation:

We have a site where the number of log-ons depends on our monthly fee. A linear relation is established between the price (log-on fee) and the number of log-ons.

We have two points for this linear relationship:

  • At price x=3, the demand is d=1100.
  • At price x=2.5, the demand is d=1375.

We will model the relation:

d=mx+b

We can calculate the slope m as:

m=\dfrac{\Delta d}{\Delta x}=\dfrac{d_2-d_1}{x_2-x_1}=\dfrac{1375-1100}{2.5-3}\\\\\\m=\dfrac{275}{-0.5}=-550

Then, replacing one point in the linear equation, we can calculate the intercept b:

d_1=mx_1+b\\\\1100=(-550)\cdot 3+b\\\\1100=-1650+b\\\\b=1100+1650=2750

Then, the linear relation between demand and price is:

d=-550x+2750

The revenue R can be expressed as the multiplication of the price and the demand:

R=x\cdot d=x(-550x+2750)=-550x^2+2750x

If we have a fixed cost of $30 per month, the profit P is:

P=R-FC=-550x^2+2750x-30

We can maximize the profit by deriving the profit function and making it equal to zero.

\dfrac{dP}{dx}=0\\\\\\\dfrac{dP}{dx}=-550(2x)+2750(1)=0\\\\\\-1100x+2750=0\\\\x=\dfrac{2750}{1100}=2.5

This corresponds to a profit of:

P(2.5)=-550(2.5)^2+2750(2.5)-30\\\\P(2.5)=-550\cdot 6.25+6875-30\\\\P(2.5)=-3437.5+6875-30\\\\P(2.5)=3407.5

5 0
3 years ago
Simplify 5+4x(8-6)^2
NARA [144]
Ok Use PEMDAS Since 8 and 6 is in pharenthesis you do that first which equals 5+4x2^2 Then you do Exponents which is 2^2 that equals 4 so that means you have 5+4x4 No you multiply 4x4 which equals 16 And now add 5 That will make 21
8 0
3 years ago
Read 2 more answers
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