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4 years ago

What's the prefix for kilo

Physics

2 answers:

m_a_m_a [10]4 years ago

4 0

Kilo means 3 and to represent it, it's a lower case "k"

Ede4ka [16]4 years ago

4 0

the prefix for Kilo is K

Like in Km: Kilometer

Kg: Kilogram

Kilo is intended for 1000 units, that is if you have 1Kg, you have 1000 g

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Write down your definition of work in the space below:

skelet666 [1.2K]

Answer:

Work is the energy transferred to or from an object via the application of force along a displacement.

5 0

3 years ago

Read 2 more answers

In the data table , distance is measured in meters and time is in seconds. Calculate the mans average velocity using the equatio

Artist 52 [7]

Answer:

3.626 m/s

Explanation:

v=d/t

1. -0.02/0 = 0 m/s

2. 0.86/0.2 = 4.3 m/s

3. 1.71/0.4 = 4.275 m/s

4. 2.54/0.6 = 4.23 m/s

5. 3.32/0.8 = 4.15 m/s

6. 4.08/1.0 = 4.08 m/s

7. 4.79/1.2 = 3.99 m/s

8. 5.48/1.4 = 3.91 m/s

9. 6.15/1.6 = 3.84 m/s

10. 6.76/1.8 = 3.76 m/s

11. 7.37/2.0 = 3.66 m/s

12. 7.92/2.2 = 3.6 m/s

13. 8.45/2.4 = 3.52 m/s

14. 8.96/2.6 = 3.45 m/s

the mean of these numbers is 3.626

his average velocity ks 3.626 m/s

6 0

3 years ago

If you ride your bike 20 miles and it takes you 120 minutes,what is your average speed

Alexus [3.1K]

120 minutes=2 hours
20/2= 10mph

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3 years ago

A mass is attached to an ideal spring. At time t = 0 the spring is at its natural length and the mass is given an initial veloci

JulijaS [17]

Answer:

t = T/4

Explanation:

The power delivered to the mass by the spring is work done by the spring per second.

$P = \frac{dW}{dt}$

The work done by the spring is equal to the elastic potential energy stored in the spring.

$U = \frac{1}{2}kx^2$

The maximum energy stored in the spring is at the amplitude of the oscillation.

$U_{max} =\frac{1}{2}kA^2$

So the first time the mass reaches to its amplitude can be found by the following equation of motion:

$x = A\cos(\omega t + \phi)\\\phi = \pi/2 ~because ~at ~t= 0, ~ x = 0\\0 = A\cos(0 + \pi/2)\\x = A\cos(\omega t + \pi/2)$

When the mass reaches the amplitude:

$A = A\cos(\omega t + \pi/2)\\1 = \cos(\omega t + \pi/2)\\\omega t + \pi/2 = \pi$

because cos(π) = 1.

$\omega t = \pi/2$

Using ω = 2π/T,

$\omega t = \pi/2\\\frac{2\pi}{T}t = \pi/2\\t = \frac{T}{4}$

4 0

4 years ago

A gas cylinder has a volume of 0.4 m? It contains butane at a pressure of 100 kPa and a temperature of

morpeh [17]

The pressure needed : 800 kPa

<h3>Further explanation</h3>

Given

V₁ = 0.4 m³

P₁ = 100 kPa

T₁ = 20 + 273 = 293 K

V₂ = 0.05 m³

T₂ = T₁ = 293 K

Required

The final pressure(P₂)

Solution

Boyle's Law

At a fixed temperature, the gas volume is inversely proportional to the pressure applied

$\tt \rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}$

Input the value :

P₂=P₁V₁/V₂

P₂=100 x 0.4 / 0.05

P₂=800 kPa

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3 years ago