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3 years ago

What are the methods of naming hydrocarbons?

Chemistry

1 answer:

seraphim [82]3 years ago

8 0

Explanation:

Hey there!

Basically, we name hydrocarbon in two ways. They are;

Trival system of nomenclature: This system was used on past. They were given name knowing their sources from which hydrocarbon are obtained. On this naming we don't use scientific rules and structural values. For example; methane was named from marsh gas.
IUPAC system of nomenclature: As the above method was not standard. IUPAC (International Union of pure and applied chemistry) improved the system and the started naming hydrocarbon. The IUPAC name of any compound contains two parts: root word and suffix. Example: Methane is named from root word Meth as it has one no.of carbon and suffix ane as it has single bonding.

Hope it helps...

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Make the following conversions. Show your calculations.

Natalija [7]

Answer:

1. 500 cm = 5 m

2. 1000 g = 1 kg

3. 455 L = 45, 500 cL

4. 0.865 m = 0.00865 m or 8.65 * 10^-3 n

5. 33.5 cm = 335 mm

6. 0.0198 m = 19800 micrometers

7. 57.65 cg = 5.765 * 10^8 nanograms

8. 1000 L = 1 kl

9. 99 degrees F = 37.222 degrees C

Explanation:

1. One meter = 100 centimeters

500 centimeters/ 100 centimeters = 5 meters

2. One kilogram = 1000 grams.

1000 grams/1000 grams = 1 kilogram

3. One Liter = 100 centiliters

455 liters * 100 centiliters = 45, 500 centiliters

4. One meter = 100 centimeters

0.865 centimeters/100 centimeters = 0.00865 meters

5. One centimeter = 10 millimeters

33.5 centimeters * 10 millimeters = 335 millimeters

6. One meter = 1.0 * 10^6 micrometers

0.0198 meters * 1 * 10^6 micrometers = 19800 micrometers.

7. One centigram = 1.0 * 10^7 nanograms

57.65 centigrams * 1 * 10^7 nanograms = 5.765 * 10^8 nanograms.

8. One kiloliter = 1000 L

1000 L/ 1000 L = 1 kiloliter

9. The formula for finding Celsius is 5/9(f - 32)

So 5/9(99 - 32) = x

5/9(67) = x

x = 335/9 or 37.222 degrees Celsius.

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Answer:

Explanation:

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3.123 gram of water will contain 2 x 3.123 / 18 = .347 g of hydrogen .

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7.691 gram of carbon dioxide will contain 12 x 7.691 / 44 = 2.1 g of carbon .

So the sample will contain 2.912 - ( .347 + 2.1 ) g of oxygen .

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